Calculating final rotational speed from angular velocity

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SUMMARY

This discussion focuses on calculating final rotational speed from angular velocity using the conservation of angular momentum. The user converted an initial speed of 1.5 revolutions per second to 9.4 radians per second. The relationship between initial and final moments of inertia (I) and angular velocities (w) is established through the equation I(initial) * w(initial) = I(final) * w(final). The final angular velocity is determined to be 3.1 rad/s when the final moment of inertia is increased by a factor of three.

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Anmol Dubey
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Homework Statement
An ice skater is spinning with a rotational speed of 1.5 rev/s. When he extends his arms and one leg, his rotational inertia increases by a factor of three. What is his final rotational speed?
Relevant Equations
Angular momentum is conserved
L = Iw
L (final) = L (initial)
I(initial)*w(initial) = I(final)*w(final)
I have no idea how to go about this. Any help would be appreciated thanks :)
Edit: I converted the 1.5 rev/s to rad/s = 9.4 rad/s
 
Last edited:
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What do you know about the quantities in your last relevant equation?
 
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Orodruin said:
What do you know about the quantities in your last relevant equation?
Like I = mr2?
w = Δθ/Δt
I didn't get what you mean by quantities
 
Anmol Dubey said:
Like I = mr2?
w = Δθ/Δt
I didn't get what you mean by quantities
No, what does the problem formulation tell you about these quantities:
I(final)
I(initial)
w(final)
w(initial)
 
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Orodruin said:
No, what does the problem formulation tell you about these quantities:
I(final)
I(initial)
w(final)
w(initial)
Since L is conserved
If I(final) is increased by a factor of 3, the w(final) is decreased by a factor of 3 so that L(final) = L(initial)
I(initial)*w(initial) = I(final)*w(final)
x*9.4 rad/s = 3x * w
so w(final) = 9.4 rad/s / 3
= 3.1 rad/s
Is that correct?
 
Anmol Dubey said:
Is that correct?
Yes.
 
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Orodruin said:
Yes.
Thank you for helping:biggrin:
 

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