Calculating Flow through a Surface with a Given Vector Field and Normal Vector

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Homework Help Overview

The discussion revolves around calculating the flow through a surface defined by a vector field F(x,y,z)=(y,xz,0) with specified borders and a normal vector. The original poster expresses uncertainty about the parametrization of the surface and the calculation of the differential area element dS.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to find the differential area element dS and considers parametrizing the surface, specifically questioning how to handle the function defined by the borders. Other participants inquire about the parametrization used and suggest using the relationship y=x to simplify the problem.

Discussion Status

Participants are actively discussing the parametrization of the surface and the calculation of the differential area. Some guidance has been provided regarding the position vector and tangent vectors, which may help clarify the original poster's approach.

Contextual Notes

The original poster mentions difficulty with the notation in LaTeX and expresses uncertainty about the boundaries and the implications of the normal vector's components.

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Homework Statement



given is the following field [tex]F(x,y,z)=(y,xz,0)[/tex] (F is a vector field) and the borders of the surface are: [tex]0<x<1 ;y=x ; 0<z<1[/tex] the < should be less equal but I don't know how to do the sign in latex, sorry. The normal vector is given as [tex]n=(a,b,c); b<0[/tex]

I shall calculate the flow through the surface

Homework Equations



the formula for the flow, can't type in in latex, sorry, but I think you know which one I mean (flow= integral F*n*dS)

The Attempt at a Solution


I need to find my dS, problem here I have, I don't know how to do this exactly. I tried to parametrize it, but I'm not sure how to do it, because I have a function in my borders. So I think y max equals 1 because of the requirements for x. Can anyone help me?
 
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If you try to use [itex]y=x[/itex] anywhere you can, it will be all quite simple.
Which parametrization did you try ?
 
I tried x,x,z not sure though.
 
That surface itself is defined by y= x. The position vector for any point on that surface is r(x, z)= <x, x, z>. Two tangent vectors, at any point are rx= < 1, 1, 0> and another is rz= <0, 0, 1>. The vector differential of surface area is given by [itex]d\vec{S}= \vec{v_s}\times\vec{v_t} dsdt[/itex]. Write your vector function in terms of s and t and integrate the dot product [itex]\vec{F}\cdot d\vec{S}[/itex]
 
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Thank you very much, that's what I did after I got the parametrisation. I wasn't sure about it though.
 

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