Calculating Fluid Flow Rates and Speeds in a Heating System

[NeedsHelp1212]

Homework Statement

Every second, 1.2 cubic meters of water enters a heating system through a pipe of medium width, A, with a cross sectional area of .2 meters squared. The water then flows into a wide pipe, B, with an area of .6 meters squared, and flows out through a narrow peipe, C, with an area of .1 meters squared.

1) what is the flow rate in each pipe?

2) what is the length of the segment of pipe A that contains 1.2 cubic meters of water? What is the length of segment B? C?

3) How much time is required for water to travel the lengths you found in pipe A? B? C?

4) What is the flow speed of water in each pipe?

5) Does the speed of water increase when it enters a narrow pipe? Does the flow rate increase? Explain.

Homework Equations

area 1 * velocity 1 = area 2 * velocity 2

The Attempt at a Solution

I have no clue how to start, i have stared at this problem for a while but I am not sure how to do it at all. I would appreciate any help.. thank you!

 

[NeedsHelp1212]

please help. I think 1 is 1.2 m^3/s

not sure about 2 so then i can't do 3 or 4. I know 5 now. I just need help with 2.

 

[NeedsHelp1212]

For 4 I used the formula A1 * v1 = a2 *v2

We know the area for the A area and the velocity as well. Since every second 1.20 m^3 of water enters i took the cube root to find how many m/s enter therefore the speed. So i found that to be 1.06 m/s. I then found the speed of B to be .353 m/s and C to be 2.12 m/s

For 2 I used formula volume = pi r^2 times length. We have the volume and the area so i just divided to get the length. For A i got 6 m, B- 2 m , C-12 m

For 3 i divided the length by the velocity for each and i got the same amount of time for each pipe (A,B,C). each being 5.66 seconds.

I think i just figured this out by myself but I would like clarification!