Calculating Fluid Force on Circular Plate in Water Tank

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SUMMARY

The discussion focuses on calculating the fluid force on a circular plate submerged in a water tank using the formula F=w∫h(y)L(y) dy. The specific parameters provided include h(y)=7-y and L(y)=2√(4-y²), leading to the integral F=2(62.4)∫(7-y)√(4-y²) dy from y=0 to y=4. Participants suggest using trigonometric substitution to solve the integral, particularly for the term ∫7√(4-y²) dy, while noting that ∫y√(4-y²) dy is straightforward.

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kari82
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Find the fluid force on the circular plate shown in figure (see attachment). Assume the plates are in the wall of a tank filled with water and the measurements are given in feet.

F=w∫h(y)L(y) dy

I have that h(y)= 7-y and L(y)=2√(4-y^2). Therefore, F=2(62.4)∫(7-y)√(4-y^2) dy from y=0 to y=4. Can someone please help me find the integrate of this equation. Thanks!
 

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hi kari82! :smile:

(try using the X2 icon just above the Reply box :wink:)
kari82 said:
… Therefore, F=2(62.4)∫(7-y)√(4-y^2) dy from y=0 to y=4. Can someone please help me find the integrate of this equation. Thanks!

you have ∫ (7 - y)√(4 - y2) dy, so just split it up …

∫ 7√(4 - y2) dy can be solved by a trig substitution, and

∫ y√(4 - y2) dy is obvious! :wink:
 

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