Calculating flux when charge on vertex of cube

[TsAmE]

Homework Statement

A point charge q = 112 x 10^-9 C is placed at the centre of a cube of side l = 0.2 m.

If the charge is moved all the way to one vertex of the cube, determine the flux
through each of the faces.

Homework Equations

None.

The Attempt at a Solution

I looked at the answer:

Flux through each face = Total flux / 24
= 2 109.23 / 24
= 527 Nm^2/C

And don't understand why the 24 is used.

I read somewhere that it said that the flux through the faces adjacent to the vertex where the charge is placed = 0, but I don't understand why? I think this might be why I don't understand the use of the "24". Could someone please help?

 

[TsAmE]

Sorry forgot to attach a diagram

 

[physicsblr]

hi!
Flux through the faces touching the charge is zero because the Electric field is parallel to them. And flux through each face = ∅/24, since you have 24 faces in the cube diagram you attached.