Calculating Force Applied to an Object of 100kg Moved 1m in 5s

Click For Summary

Discussion Overview

The discussion revolves around calculating the force applied to a 100kg object that is moved or lifted a distance of 1 meter over a duration of 5 seconds. Participants explore various aspects of the problem, including the relevance of time, velocity profiles, and the effects of gravity, while considering different scenarios such as constant acceleration and constant velocity.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant questions how to find the force applied, noting that force values are typically provided to calculate work done and power.
  • Another suggests using SUVAT equations to find acceleration based on distance and time, but questions the relevance of time without knowing the final speed.
  • Some participants highlight the need for a specified velocity profile, indicating that there are infinite ways to move the object from point A to point B.
  • A participant mentions that to lift the object, one must consider both the force required to lift it and the weight due to gravity.
  • There is a discussion about calculating average acceleration and the conditions under which it can be determined, with some asserting that initial and final velocities are necessary for accurate calculations.
  • One participant calculates an acceleration of 0.08 m/s² and a force of 8N but questions whether this should be combined with the weight of the object.
  • Another participant emphasizes the need to clarify the problem statement and the assumptions made in the calculations.
  • There is a reiteration that for the object to be moved, it must be supported against gravity, leading to a force of 980N, and that additional forces may be needed for acceleration and deceleration.

Areas of Agreement / Disagreement

Participants express differing views on how to approach the problem, with no consensus on a single method or solution. There is acknowledgment of the complexity involved in defining the problem fully, particularly regarding initial and final velocities and the effects of gravity.

Contextual Notes

Participants note limitations in the problem statement, including unspecified initial and final velocities, which affect the ability to calculate acceleration and force accurately. The discussion reflects a range of assumptions and conditions that are not fully defined.

Who May Find This Useful

This discussion may be useful for individuals interested in physics problem-solving, particularly those grappling with concepts of force, motion, and the application of equations of motion in various scenarios.

Chandrasekar
Messages
13
Reaction score
1
TL;DR
how to find how force applied on an object?
if an object of 100kg is moved or lifted to a distance of 1m taken 5s, then how can i find the amount of force applied to the object.
in every problem i noticed, force value is given to find the Workdone and the Power.
I think it is simple problem, but i can't find it simple. can anyone clear this problem?
 
Physics news on Phys.org
Use one of the SUVAT equations to find the acceleration.
You have the distance travelling in a set time.
 
Reply
  • Like
Likes   Reactions: malawi_glenn
Why is time relevant?

What is the final speed of the object?
 
One note: if not given a velocity (acceleration) profile you will have to make your own and there are an infinite number of ways to get from point A to point B.
 
Last edited:
Reply
  • Like
Likes   Reactions: nasu, Lord Jestocost and erobz
Frabjous said:
If you know distance and time, you can calculate average acceleration.
One solves the problem one is given, not the problem one wants.
I was asking the OP in order to help him/her figure it out.

Average acceleration? That depends on the initial and final velocities, not displacement or time.

In order to lift an object of mass 100 kg upwards, should I ignore gravity?
 
Last edited:
Reply
  • Like
Likes   Reactions: russ_watters
Chandrasekar said:
...if an object of 100kg is moved or lifted to a distance of 1m taken 5s, then how can i find the amount of force applied to the object.
The initial or final velocity are not specified.
If the mass was initially travelling upwards with a fixed velocity of 0.2 m/s, and maintained that upward velocity throughout the process, then would the force not be; F = m·g = 980 N.
 
Reply
  • Like
Likes   Reactions: jbriggs444 and malawi_glenn
Chandrasekar said:
TL;DR Summary: how to find how force applied on an object?

if an object of 100kg is moved or lifted to a distance of 1m taken 5s, then how can i find the amount of force applied to the object.
There are two different questions here. If the object is moved over a (horizontal) distance and there's no friction AND we assume constant acceleration then the SUVAT equations will tell you that acceleration. Then the Force is ma.
If it's lifted then you need that same force plus the weight of the object. Of course, we are assuming that the object starts off stationary. To get the answer, the question needs to be specified fully.

Any decent text book will (or should) give you questions that are properly defined and for which there is just one correct answer but, if you are trying to deal with a practical situation of your own then defining the question is more up to you - we've all had the experience of getting more than one answer to this sort of problem and then had to go back and decide what the question was exactly. Can be difficult, sometimes, particularly in real life situations with motor cars and electric motors where you just don't expect constant acceleration. SUVAT goes out of the window for a start. :confused:
 
Sorry guys for late replay.

russ_watters said:
One note: if not given a velocity (acceleration) profile you will have to make your own and there are an infinite number of ways to get from point A to point B.
Baluncore said:
The initial or final velocity are not specified.

considering constant velocity. then what do i do next?. sorry for my inability to understand.

Baluncore said:
If the mass was initially travelling upwards with a fixed velocity of 0.2 m/s, and maintained that upward velocity throughout the process, then would the force not be; F = m·g = 980 N.

sorry, is this a question for me?.

sophiecentaur said:
If it's lifted then you need that same force plus the weight of the object. Of course, we are assuming that the object starts off stationary. To get the answer, the question needs to be specified fully.
sophiecentaur said:
if you are trying to deal with a practical situation of your own then defining the question is more up to you - we've all had the experience of getting more than one answer to this sort of problem and then had to go back and decide what the question was exactly.

sorry, i don't have definite data to ask correct question with my understanding. if anyone says 'i have missed this data to solve this problem with this formula' it will be easy for me to understand - i think.

sophiecentaur said:
If the object is moved over a (horizontal) distance and there's no friction AND we assume constant acceleration then the SUVAT equations will tell you that acceleration. Then the Force is ma.

i have got a=0.08 by considering u=0 using formula s=ut+0.5at^2. then got F=8N, is this correct? do i have to add this with weight of the object?[/QUOTE]
 
Last edited by a moderator:
Chandrasekar said:
Sorry guys for late replay.

considering constant velocity. then what do i do next?. sorry for my inability to understand.
sorry, is this a question for me?.

sorry, i don't have definite data to ask correct question with my understanding. if anyone says 'i have missed this data to solve this problem with this formula' it will be easy for me to understand - i think.
i have got a=0.08 by considering u=0 using formula s=ut+0.5at^2. then got F=8N, is this correct? do i have to add this with weight of the object?
Is this a homework problem? If it is, is this the full problem statement? You don’t seem to have connected the dots on what was told to you, and everyone is trying to make an educated guess as to what the full problem statement is supposed to be. We need some clarification.
 
Reply
  • Like
Likes   Reactions: malawi_glenn, sophiecentaur, SammyS and 1 other person
  • #10
this is not a
erobz said:
Is this a homework problem? If it is, is this the full problem statement? You don’t seem to have connected the dots on what was told to you, and everyone is trying to make an educated guess as to what the full problem statement is supposed to be. We need some clarification.
this is not a homework problem, just questioned myself on how to find it.

I think i'm unable find the pattern in the dots.

i humbly request someone to explain my misconception on this topic.
 
  • #11
For the 5 seconds the mass is being moved, you must support it against gravity with a force of; F = m·g = 980 N.

NOW you must specify the initial and final velocities.
If they are zero, then you must use a force to accelerate the mass, and then an opposite force to decelerate the mass, so that it moves a total of 1 metre in 5 seconds.

The acceleration force will be the negative of the deceleration force, so they will cancel. So the average force during the movement will be; F = m·g = 980 N.
 
Reply
  • Like
Likes   Reactions: Chandrasekar
  • #12
Chandrasekar said:
this is not a

this is not a homework problem, just questioned myself on how to find it.

I think i'm unable find the pattern in the dots.

i humbly request someone to explain my misconception on this topic.
Homework or not, we aren't going to do it for you. You got a lot of good responses and need to make an effort to address them.
 
Reply
  • Like
Likes   Reactions: Chandrasekar
  • #13
Chandrasekar said:
TL;DR Summary: how to find how force applied on an object?

if an object of 100kg is moved or lifted to a distance of 1m taken 5s, then how can i find the amount of force applied to the object.
in every problem i noticed, force value is given to find the Workdone and the Power.
I think it is simple problem, but i can't find it simple. can anyone clear this problem?
You need to learn physics to do physics.
 
Reply
  • Like
Likes   Reactions: vanhees71

Similar threads

High School Lever balancing physics (video game design)
  • · Replies 18 ·
Replies
18
Views
3K
High School Lifting an object with a mass difference of just 1kg
  • · Replies 6 ·
Replies
6
Views
1K
Undergrad A Question About the Physical Explanation Behind Torque
  • · Replies 8 ·
Replies
8
Views
2K
Undergrad How to Calculate force exerted on a falling body?
  • · Replies 12 ·
Replies
12
Views
3K
Undergrad Mechanical power generated by a force F
  • · Replies 41 ·
2
Replies
41
Views
4K
Undergrad Force applied on sphere by turbulent flow
  • · Replies 28 ·
Replies
28
Views
2K
High School What is the Definition of the Joule and How Does it Relate to Energy?
  • · Replies 15 ·
Replies
15
Views
3K
Undergrad Origin of Centripetal force when the net force toward the center is 0?
  • · Replies 8 ·
Replies
8
Views
3K
Undergrad What is the top velocity of an object with a certain force applied in a vacuum?
  • · Replies 8 ·
Replies
8
Views
2K
Undergrad Question about driven harmonic oscillator
  • · Replies 17 ·
Replies
17
Views
3K