Calculating Force - Basketball player landing from a jump

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SUMMARY

The discussion centers on calculating the gravitational force acting on a basketball player with a mass of 112 kg who jumps to a height of 0.92 m. The correct formula to determine the force is \(\vec f = m \vec g\), where \(g\) is the acceleration due to gravity (9.8 m/s²). The height of the jump does not affect the calculation of the gravitational force, which is consistently 1098 N. The consensus is that the height is irrelevant for this specific calculation.

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Homework Statement


Ok, relatively simple question here, but I have a newb doubt...

"A basketball player with a mass of 112kg can jump 0.92 m into the air during a slam dunk competition. Calculate the force that pulls the player back towards the floor."

Homework Equations


## \vec f = m \vec g##

The Attempt at a Solution


Is the 0.92 m height a red herring distraction?

If so it's just a straightforward 112 kg x 9.8 m/s^2 = 1098 N answer.

Am I correct to ignore the 0.92 m height?

Apologies in advance for such a basic question.
 
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It is absolutely a red herring. The force of gravity on the player close to the surface of the Earth is always his mass multiplied by g.
 
Thank you very much for your patient reply.
 

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