Calculating Force in the Turning Effect of Force Equation

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To calculate the force in the turning effect of force equation, the relationship F1D1 = F2D2 is used, where F1 is 7.2 N and D1 is 1.0 cm, while D2 is 8.0 cm. The calculated force F is 0.9 N, but there is confusion regarding the distances used. It is confirmed that both distances D1 and D2 should be measured from the pivot point, which are correctly identified as 1.0 cm and 8.0 cm, respectively. The total distance from the unknown force F to the pivot point is 9.0 cm. Understanding these parameters is crucial for solving similar problems confidently in the future.
Muhammad Danish
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Homework Statement


upload_2018-4-15_22-34-13.png


Homework Equations


How do we calculate the value of F?

The Attempt at a Solution


Since for an object to be in equilibrium, F1D1 = F2D2 so 7.2 x 1 = F x 8
F = 0.9N, I am pretty much confused with the answer I worked out. If I am wrong or if I am right, please explain me the correct solution so that next time before solving questions of this type, I would be confident.

Thanks.
(Regards)
 

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Both D1 and D2 should be distances as measured from the pivot point. Check to make sure you have the correct values for D1 and D2.
 
TSny said:
Both D1 and D2 should be distances as measured from the pivot point. Check to make sure you have the correct values for D1 and D2.
Yes, the correct values of D1 and D2 are 1.0 cm and 8.0 cm respectively.
 
Muhammad Danish said:
Yes, the correct values of D1 and D2 are 1.0 cm and 8.0 cm respectively.
What is the distance between the unknown force F and the pivot point?
 
TSny said:
What is the distance between the unknown force F and the pivot point?
Oh, It will be 8+1= 9.0 cm?
 
Muhammad Danish said:
Oh, It will be 8+1= 9.0 cm?
Yes.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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