Calculating Force of Stifled Sneezes

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SUMMARY

The discussion centers on calculating the outward force exerted on the eardrum when a sneeze is stifled, resulting in a pressure of 45 kPa. The participant derived a force of 2.5 N using the formula F = Pressure × Area, where the area was calculated based on the diameter of the eardrum (0.0084 meters). The calculations were confirmed to be reasonable, correlating to a mass of approximately 250 grams, which raises concerns about the potential damage to the eardrum. The textbook "Physics for Scientists and Engineers" by Knights, Jones, and Field was referenced for additional context.

PREREQUISITES
  • Understanding of basic physics concepts such as pressure, force, and area.
  • Familiarity with the ideal gas law (PV=nRT) and its applications.
  • Knowledge of the relationship between pressure and work in physics.
  • Ability to perform calculations involving units of pressure (Pa) and force (N).
NEXT STEPS
  • Review the textbook "Physics for Scientists and Engineers" by Knights, Jones, and Field for relevant examples.
  • Learn about the effects of pressure on biological tissues and the implications of stifling sneezes.
  • Explore the derivation and application of the formula F = Pressure × Area in various contexts.
  • Investigate the physiological consequences of high-pressure scenarios on the human body.
USEFUL FOR

Students studying physics, medical professionals interested in human anatomy, and anyone curious about the effects of pressure on delicate biological structures.

donkey11
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Homework Statement


When you stiffle a sneeze, you can damage delicate tissues because the pressure of the air that is not allowed to escape can raise up to 45kpa, if this extra pressure acts on the inner parts of your 0.0084 meter diameter of your eardrum, what is the outward force?


Homework Equations


work= Pressure * Volume
Force= work/ circumference
pv=nRT

The Attempt at a Solution



i have no idea where to start, i know that pressure is related to work by volume but i do not have any measurements for volume, i know i can get volume but i do not know temperature or amount of moles, i know i can said p1v1=p2v2 but i do not know the original pressure or original volume to make that assumption. I just need to know what to look at to start the problem Thanks!
 
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i also have the formula p=F/Area
 
i think i have solved it by using F= pressure (pie * d/2^2) to get a value of 2.5 N, that kinda seems small but also the area is quite small could anyone tell me if this is a reasonable answer
 
Your pressure seems to be correct this corresponds to a mass of about 250 grams. Quite a lot for such a delicate membrane would'nt you think?
 
Is it 2.5 kN?
 
i think its only 2.5 n as i made my transformation of 45 kpa to 45000 pa
 
There is an example in the textbook.. the one by knights jones and field.. is that what you're using? anyway, there was an example in the book where it was Pa multiplied by meters squared and equaled Newtons... i don't have the book or else i'd tell you the page!
 

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