Calculating Force on a Sphere with 1 Bar Pressure

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SUMMARY

The force exerted on a sphere can be calculated using the formula: Force = Pressure × Area. In the context of a pneumatic air rifle, with a projectile diameter of 6mm, the effective cross-sectional area is 5.65 × 10-5 m2. For a pressure difference of 1 bar, the force acting on the projectile is derived from this area, confirming that the cross-sectional area is the correct measurement for force calculations, rather than the hemisphere's surface area.

PREREQUISITES
  • Understanding of basic physics principles, specifically force and pressure.
  • Familiarity with the formula for calculating area of a circle.
  • Knowledge of pneumatic systems and their components.
  • Basic mathematical skills for unit conversions and calculations.
NEXT STEPS
  • Research the effects of different pressures on projectile acceleration in pneumatic systems.
  • Learn about the principles of fluid dynamics as they apply to air pressure and force.
  • Explore the design considerations for pneumatic air rifles, including barrel length and projectile weight.
  • Investigate the impact of different projectile materials on performance and accuracy.
USEFUL FOR

This discussion is beneficial for engineers, hobbyists, and designers involved in pneumatic systems, particularly those focused on air rifle mechanics and projectile dynamics.

cheekibreeki
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Hey people, first post, I'm sorry if I'm posting this in the wrong place.

How do you calculate the force exerted on a sphere? I'm building a pneumatic air rifle, and I'm trying to figure out how fast an airsoft bb accellerates with a certain pressure.

The projectile is 6mm in diameter, so that makes the surface on which the air pressure works 1/2 * (4 * pi * 3^2) = 1/2 * 113.1 = 56.5 mm^2 = 5.65 * 10^ -5 m^2.

What is the force on the projectile if the difference in pressure is 1 bar?
 
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cheekibreeki said:
surface on which the air pressure works 1/2 * (4 * pi * 3^2) = 1/2 * 113.1 = 56.5 mm^2 = 5.65 * 10^ -5 m^2.
It's an attractive notion to use the area of the hemisphere, an it's also incorrect. The area on which the pressure acts is the cross-sectional area of the projectile, period. Force then is pressure times area of the bore.
 
Thanks, that makes things a whole lot easier!
 
Just in case you're curious:
The force from the pressure acts perpendicular to the surface, so if you were to use the surface area of the hemisphere, you would have to use only the component of force that acts along the barrel. If you do the math it reduces to using the cross-sectional area.
 

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