Calculating Forces: Door Acceleration and Friction on a Horizontal Surface

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Homework Help Overview

The discussion revolves around calculating forces related to a door being kicked and the frictional force acting on an object moving at constant velocity on a horizontal surface. The subject area includes concepts from dynamics and friction in physics.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationship between applied forces and the forces exerted by objects in response, referencing Newton's laws of motion. There are attempts to clarify concepts like inertia and the nature of forces acting in opposite directions. Some participants express confusion and seek simpler explanations.

Discussion Status

There is ongoing exploration of the concepts involved, with some participants providing insights into Newton's laws. However, several participants indicate a lack of understanding and request further clarification. No explicit consensus has been reached on the specific solutions to the problems posed.

Contextual Notes

Participants mention language barriers and varying levels of familiarity with physics terminology, which may affect comprehension of the concepts discussed.

chrono4321
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im new to da whole physics ding...and i need help with it

A person kicks a 4.0-kg door with a 48Newton force causing the door to accelerate at 12 meters per second. WHat is the magnitude of the forces exerted by the door on the person? (Answer in Newtons)

and this one too

A 50.-Newton horizontal force is needed to keep an object weighing 500. Newtons moving at a constant velocity of 2.0 meters per second across a horizontal surface. The magnitude of the frictional force acting on the object is (Answer in Newtons)

Thx guys i really need this.
 
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If a force is moving something at constant velocity (speed), then there must be an opposite force of equal magnitude, otherwise there would be a net positive which would cause a mass to accelerate.

Kicking the door is an example of impulse. The product of mass and acceleration = force, and the door imposes a force in opposition to the applied force.
 
i still dun really understand...can u put it in simpler terms or sumthing? thanks
 
When one pushes on an object is resists the push, and effectively pushes back.

Do you understand the concept of inertia, and how force, mass and acceleration are related?
 
i still dun get how to answer my questions
 
i still dun get it =(
 
when one exerts a force on something, that thing exerts the same force but opposite in direction

if you exert 12N upon the door, it also exerts 12N on you, but in the opposite direction. (otherwise it would crack into many pieces)

EDIT: I am not saying 12 N is the answer, i just picked a random number
 
as for your second question...

Ff (frictional force)= mass(im pretty sure this has to be in kg) x uk(coefficient of friction)
 
Last edited:
Is this same as Newton Second Movement Rule? If yes then i know how the solution. if No then i don't know the solution. Sorry my physics in not english but in malay
 
  • #10
Mmx said:
Is this same as Newton Second Movement Rule? If yes then i know how the solution. if No then i don't know the solution. Sorry my physics in not english but in malay

The second question is related to Newton's second law, the first question is better suited to Newton's third law.
 

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