Calculating Forces on a Uniform Platform in Equilibrium: Physics Problem

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Homework Help Overview

The discussion revolves around calculating the forces exerted on a uniform platform in equilibrium, specifically focusing on a scenario where a person stands on the platform. The problem involves determining the forces at both ends of the platform, given its mass and the mass of the person.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss summing moments about different points to isolate variables and check calculations. Questions arise regarding the logical consistency of negative force values and the representation of forces in terms of mass and gravity.

Discussion Status

Some participants provide guidance on simplifying the problem and suggest checking calculations against different methods. There is acknowledgment of potential errors in the values obtained for the forces, particularly regarding the interpretation of negative values.

Contextual Notes

Participants are working under the constraints of a homework problem, which may limit the information available for discussion. There is an emphasis on ensuring that the calculations align with physical expectations.

key
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a person stands a distance of 0.300 meters from the right end of a 2.00 meter long uniform platform that is supported by two posts, one at each end. The board has a mass of 20.0 kg and the person's mass is 75.0 kg.

a. determine the force exterted on the board by the post on the left end.

b. determine the force exerted on the board by the post on the right end.



Sum moments about any point. I will choose the Right end.

-.3*75g -1*20g+Fleft*2=0

That gives you Fleft end.

Now, sum forces vertically
Fleft+Fright-20g-75g=0
solve for fright.

i don't think I'm doing it right
can someone help
 
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Hi key, well I think you simply over complicated things actually, have a look back at you first equation, isn't that already solvable, you did exactly the right thing by taking moments about the right post you eliminated the right reactive force from you equations leaving you with a single variable :D which is solvable on its own, and repeat to find the right hand force, hope that helps :D
 
As Galadirith has noted, you can sum moments about the left post to solve for F-right, and then this serves as a check for your value you obtained for F_right when you summed forces in the y direction, which is also correct. It's good to have a backup equation for a check; if the value obtained for F_right is different when using the sum of moment equation than it is when using the sum of forces equation, you made an error somewhere.
 
I got 21.25 for F left and -73.75 for F right.
Is that right?
 
Hi key, well i think you are basically there but a couple of things to say. Firstly the value reactive force at the right post you gave that as -73.75, i would suggest have a look at that again, and think does it seem logical that the reactive force is negative? Also you have given numerical values in terms of g, basically in you original equations you correctly set up the equation for moment about the right post, with their forces expressed in terms of their respective masses and the acceleration due to gravity represented by g.

In order for you final values of the forces to be correct it would either be 21.25g N or 208.25 N, hopefully you can see why and verify that for yourself, the same also applies to the right post. :D
 

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