Calculating Forces on Boxcars in a Train: Newtons and Acceleration

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A train consists of a 4300kg locomotive pulling two loaded boxcars. The first boxcar has a mass of 12,700kg and the second 16,300kg. Presume that the boxcar wheels roll without friction and ignore aerodynamics. The acceleration of the train is 0.578m/s^2
a)With what force, in Newtons, do the boxcars pull on each other?

I am confused here. Do they pull on each other with the same force? They can't since they don't weigh the same, correct?

0.578=T/12700 T=7340.6

0.578=T/16300 T=9421.4


b) With what force do the locomotive and first boxcar pull on each other?

I can use the same steps from a) for this one

c)With what force must the tracks push on the locomotive?

would the force be equal to the weight?
 
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waldvocm said:
Do they pull on each other with the same force? They can't since they don't weigh the same, correct?
What does Newton's 3rd law tell you?

0.578=T/12700 T=7340.6

0.578=T/16300 T=9421.4
Don't confuse the net force on a car with the force between the cars.

First things first. Draw diagrams of each car, showing the forces acting on it. Then apply Newton's laws as needed.
 
a) boxcars pull on each other
F=16300(0.578)=9421.4

b)The locomotive pull on the first boxcar
F=12700+16300(0.578)=16762

c)The tracks push on the locomotive
F=4300(9.80)=42140

Are these formulas correct?
 
waldvocm said:
a) boxcars pull on each other
F=16300(0.578)=9421.4

b)The locomotive pull on the first boxcar
F=12700+16300(0.578)=16762

c)The tracks push on the locomotive
F=4300(9.80)=42140

Are these formulas correct?
The first answer is correct, but the others are not. I suggest that you label the forces--for example, F1-2, FL-1, and Ft-L--then write force equations for each car.