Calculating Friction Coefficient with 40 N Force and 5 kg Box

[kirstynl]

okay, i tried searching knietic energy and it won't come up,
soooo here's a questions:


a force of 40 N continues to push a 5 kg box and acclerates it a .70 m/s/s what is the coefficient of friction/

i got the static because it wasn't movingm, but i have no idiea how to get that please help

 

[Shooting Star]

First, tell us what was the net force acting on the body.

 

[HallsofIvy]

This problem has nothing to do with kinetic energy! As shooting star said (I seem to spending the day right behind him!), it is entirely a matter of force. What is the net force on the body? Also I have no idea what you mean by "I got the static because it wasn't moving". What wasn't moving? What "static"?

 

[Shooting Star]

i got the static because it wasn't movingm, but i have no idiea how to get that please help

Do you by chance mean you "get" the case for static friction? Anyway, reply to our questions if you want to understand the problem.

 

[will.c]

if the acceleration is .7 m/s^2, and the box has a mass of five kilograms, Newton will only take a second to tell you the net force on the box.

Of course, if there's a difference between the applied force and the net force, there must be another force acting on the box. This is where you'll find your kinetic friction.