Calculating Frictional Force and Coefficient of Friction | Quick Homework Help

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Homework Help Overview

The discussion revolves around calculating the frictional force and the coefficient of friction for a block being accelerated by a force on a horizontal surface. The problem involves understanding the relationship between applied force, friction, and acceleration.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the total force acting on the block and question the provided information. There are attempts to relate the applied force and frictional force through equations of motion.

Discussion Status

Some participants have offered guidance on how to approach the problem, suggesting the need to equate forces and solve for unknowns. There is an acknowledgment that the original poster has more information to work with than initially presented.

Contextual Notes

There is a mention of the need for the original poster to engage with the problem further, indicating that the discussion is still open and exploratory.

jayyafeelme
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Homework Statement



A force of 43.0 N accelerates a 5.0-kg block at 6.1 m/s2 along a horizontal surface.
How large is the frictional force?

What is the coefficient of friction?

Homework Equations


F = ukFn

The Attempt at a Solution


Fthrust = Ffriction = ukFn = ukFg = uk x m x g = ? x 5.0 kg x 6.1 m/s/s
 
Last edited:
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no one can help me?
 
bump. i need help please
 
What's the total force on the block?
 
43 N i think. that's all the givens i have
 
No, you clearly have more "givens." And 43 N is NOT the total force.
 
here the net force of the system is ma

take the forces, -------->u have the applied force...(43N) and the force against it which u don't have (Ff) and equate it to the net force

so, ma = Fapplied - Ffriction

i thinks that's how u solve it...i can be wrong...

once you solve for friction force, you can easily solve for mu by with Ff = muFn
 
Yes, that's how you solve it, but it gives a bit too much information. The poster has to do some work too!
 

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