Calculating Frictional Force: L, Lh, Lv, m

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The discussion focuses on calculating the frictional force acting on a ladder, specifically in terms of its length (L), horizontal distance (Lh), vertical distance (Lv), and mass (m). The participants emphasize that when the ladder is stationary, the sum of the horizontal forces, vertical forces, and torques must equal zero. By establishing and solving these equations, one can determine the force F and the coefficient of friction necessary to prevent the ladder from slipping. Additionally, the forces acting on the wall are also considered in the calculations.

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Look at line a,assume it is not sliding down.Line b is sliding down,which means the frictional force of floor is smaller than F.
Line is of mass 1kg.Length is 2m, so C.M is in 1m
How do you find the force F interms of L,Lh, Lv,m each case?
L is the length of line. Lh is the horizontal distance. Lv is Vertical distance.
This is not a Home work Question or Homework type question .
I am just curious.
 

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You also need to consider the force on the wall.

If the ladder isn't moving (yet) then three things sum to zero..

The horizontal components of the forces
The vertical components of the forces
The torques.

By writing and solving these equations you can solve for the force F or work out the coefficient of friction required to stop the ladder slipping etc
 
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CWatters said:
You also need to consider the force on the wall.

If the ladder isn't moving (yet) then three things sum to zero..

The horizontal components of the forces
The vertical components of the forces
The torques.

By writing and solving these equations you can solve for the force F or work out the coefficient of friction required to stop the ladder slipping etc
Great Idea.Thanks.
 

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