Calculating Frictional Force on a Moving Car on a Slope

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SUMMARY

The discussion focuses on calculating the frictional force acting on a 2,254-kg car moving down a 10-degree slope with an acceleration of 1.1 m/s². The frictional force is determined using the equation μ = ax / (g cos θ - g sin θ), resulting in a coefficient of friction (μ) of 0.138. Participants emphasize the importance of visualizing the problem through a free body diagram to clarify the forces at play. This structured approach aids in accurately calculating the frictional force in the context of physics problems involving slopes.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with free body diagrams
  • Knowledge of trigonometric functions (sine and cosine)
  • Basic grasp of frictional force concepts
NEXT STEPS
  • Study the derivation of frictional force equations in physics
  • Learn how to construct and analyze free body diagrams
  • Explore the effects of different angles on frictional force calculations
  • Investigate real-world applications of friction in automotive dynamics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators and anyone interested in understanding the dynamics of vehicles on slopes.

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Homework Statement


A 2,254-kg car is moving down a road with a slope of 10 degrees while speeding up at a rate of 1.1 m/s^2. What is the direction and magnitude of the frictional force?
(define positive in the forward direction, i.e., down the slope)?


Homework Equations


ax=μgcos-gsin


The Attempt at a Solution


μ=ax/gcos-gsin 1.1m/9.81(cos10-sin10)=0.138 i keep on getting this answer.
 
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I think it would be useful if you provided more details about your attempt. For starters, what does the free body diagram look like?
 

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