Calculating harmonics of a copper wire

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SUMMARY

The discussion focuses on calculating the wavelength of the third harmonic for a 1.13m length of 18-gauge copper wire under different tensions. Initially, the wavelength is calculated using the formula λ = (2L)/n, yielding 0.75m for a 200N ball. When replacing the ball with a 1000N weight, the tension alters the wire's length slightly, impacting the wavelength. The ambiguity in whether the stated length is under tension or not is noted, emphasizing the importance of Young's modulus in determining the wire's behavior under varying loads.

PREREQUISITES
  • Understanding of harmonic frequencies and wavelengths
  • Familiarity with Young's modulus and its application in material science
  • Knowledge of tension effects on string length and wave properties
  • Proficiency in using the formula λ = (2L)/n for harmonic calculations
NEXT STEPS
  • Research the effects of tension on the wavelength of vibrating strings
  • Study Young's modulus and its implications for different materials
  • Explore the relationship between frequency, tension, and wavelength in wave mechanics
  • Investigate how to experimentally measure changes in wire length under different loads
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Physics students, material scientists, and engineers interested in wave mechanics and the properties of materials under stress.

gboff21
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Homework Statement


A vertical, 1.13m length of 18-gauge (diameter of 1.024mm) copper wire has a 200.0N ball hanging from it.

What is the wavelength of the third harmonic for this wire?

A 1000- ball now replaces the original ball. What is the change in the wavelength of the third harmonic caused by replacing the light ball with the heavy one? (Hint: See Table 11.1 in the textbook for Young's modulus.)


Homework Equations


[lambda=(2L)/n

L=length of string
n=harmonic number


[h2]The Attempt at a Solution[/h2]

1. lambda=(2L)/n
so =2/3*1.13=0.75m
But the next question implies that it's related to tension. How?

 
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gboff21 said:

Homework Statement


A vertical, 1.13m length of 18-gauge (diameter of 1.024mm) copper wire has a 200.0N ball hanging from it.

What is the wavelength of the third harmonic for this wire?

A 1000- ball now replaces the original ball. What is the change in the wavelength of the third harmonic caused by replacing the light ball with the heavy one? (Hint: See Table 11.1 in the textbook for Young's modulus.)


Homework Equations


[lambda=(2L)/n

L=length of string
n=harmonic number


[h2]The Attempt at a Solution[/h2]

1. lambda=(2L)/n
so =2/3*1.13=0.75m
But the next question implies that it's related to tension. How?
The formula

λ = 2L/n (where n = 1 corresponds to the fundamental wavelength)​

applies the same regardless of the tension.

But what's different when you replace the 200 N ball with a 1000 N ball is the length of the copper wire changes a little bit. In other words, L is not the same in each case.

(The frequency of the wave changes a lot. The wavelength only changes a little, but it does change because L changes a little.)

The thing which I question is whether the problem statement claims that length is 1.13 m when tension free, or if it is 1.13 m when the 200 N ball is already hanging. It sort of sounds to me like the wire is 1.13 m when the 200 N ball is already hanging. That's my guess anyway. But it's only a guess. The problem statement is kind of ambiguous regarding this. Perhaps your coursework has a figure or something that would make it more obvious which one it is. You'll have to determine which one, because it makes a difference.

Whatever the case, you can use Young's modulus to find the relationship between the tension on the wire and its length. Once you know the wire's length repeat what you did above to find the wavelength of the third harmonic.
 

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