Calculating Heat Capacity for Cage Weight of 1000 kg at 9 m/s

[Scarlet_pat]

Homework Statement

in the absense of bearing friction a winding engine would raise a cage weighing 1000 kg at 10m/s, but this is reduced by friction to 9 m/s, how much oil, initially at 20 C is required per second to keep the temperature of the bearing down to 70 C
(specific heat capacity of oil is 2100 J/Kg K , g = 9.81 )

Homework Equations

heat energy = mass x specific heat capacity x change of temperature

The Attempt at a Solution

i personally do not know how to attempt this question, i was trying to see if there is any relationship between velocity and energy, but i couldn't find anything. please .. help

 

[RobL14]

The work done by friction is equal to the energy released as heat. Calculate the work done by friction using conservation of energy, then go from there.

 

[Scarlet_pat]

The work done by friction is equal to the energy released as heat. Calculate the work done by friction using conservation of energy, then go from there.

first of all, thank you very much, but yet still i didnt get the correct answer. therefore i would like to find out if i was in the right direction

1. by using linear motion equation : v^2 = u^2 +2as
solved for S : s = v^2-u^2/2a

when distance is found. i calculated the force = mg

word done by the friction is equal to the heat energy therefore : force = mg x S

since heat energy is found. equation ... Heat energy = m c ( theta temp ) was used
solve for mass
M = heat energy / c ( theta temp.)
am i correct?

 

[Scarlet_pat]

first of all, thank you very much, but yet still i didnt get the correct answer. therefore i would like to find out if i was in the right direction

1. by using linear motion equation : v^2 = u^2 +2as
solved for S : s = v^2-u^2/2a

when distance is found. i calculated the force = mg

word done by the friction is equal to the heat energy therefore : force = mg x S

since heat energy is found. equation ... Heat energy = m c ( theta temp ) was used
solve for mass
M = heat energy / c ( theta temp.)
am i correct?