Calculating Heat Flow in Snow: 0°C & 37°C

Click For Summary

Homework Help Overview

The problem involves calculating heat flow between a person's foot at 37°C and snow at 0°C, considering the thermal properties of the shoe sole. The context is heat conduction in a thermal physics scenario.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the direction of heat flow and the relevance of the shoe sole's thickness and area in the calculations. There is uncertainty about whether to calculate the volume of the sole and how to apply the heat conduction equation.

Discussion Status

Some participants have provided guidance on the heat conduction equation and suggested alternative ways to express temperature differences. Multiple interpretations of the problem are being explored, particularly regarding the variables involved in the heat conduction formula.

Contextual Notes

Participants are grappling with the specifics of the heat conduction equation and the implications of the given parameters, such as thermal conductivity and temperature difference.

Revolt
Messages
7
Reaction score
0

Homework Statement



a person with a body temp of 37 degrees stands on snow with a temp of 0 degrees
each of there shoes has a sole 1cm thick with an area of 300cm^2 and a 0.2 thermal conductivity
what is the magnitude and direction of heat flow

Homework Equations





The Attempt at a Solution



right well obviously the direction is into the ground, heat travels from hot to cold

now I am not sure if you need to calculate the volume of "sole" which the heat is being conducted through or not and that has me stumped as its the first hurdle at which I am clueless!
 
Physics news on Phys.org
What equation describes heat conduction?
 
dQ/dt = -kA dT/dx

if a is the cross sectional area of the sole of the shoe do you then not need the thickness of it ? ;s and dT/dx would be the rate of change of temperature, however I am unsure as to what the rate of change is as all your told is it changes from 37 to 0

ive hit a brick wall with this one !
 
Instead of dT/dx, write it as [itex]\Delta T/\Delta x[/itex]. That's temperature difference over thickness.

For more, read Heat Conduction.
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
5K