Calculating Heat of Object in Re-Entry: Kelvin °

  • Thread starter Thread starter nicholas0211510
  • Start date Start date
  • Tags Tags
    Heat
Click For Summary
SUMMARY

The calculation of heat during atmospheric re-entry is primarily based on the principles of stagnation temperature and the effects of compression rather than friction. The Space Shuttle's ablative tiles experienced surface temperatures around 2000K during re-entry, while meteors can reach approximately 5000K, as estimated through color analysis using Wien's law. Understanding the pressure in front of the object is crucial for determining the temperature of the air and the corresponding heat experienced by the object. NASA provides resources on stagnation temperature, which is essential for accurate calculations in this context.

PREREQUISITES
  • Understanding of stagnation temperature and its significance in fluid dynamics
  • Familiarity with Wien's law for estimating temperatures based on color
  • Knowledge of atmospheric re-entry dynamics and heat transfer principles
  • Basic concepts of pressure and its relationship to temperature in gases
NEXT STEPS
  • Research NASA's resources on stagnation temperature and its calculations
  • Explore the principles of blackbody radiation and its applications in thermal analysis
  • Study the effects of atmospheric pressure on temperature during re-entry
  • Learn about the thermal protection systems used in spacecraft, such as ablative materials
USEFUL FOR

Aerospace engineers, physicists, and students studying thermodynamics and fluid dynamics will benefit from this discussion, particularly those interested in atmospheric re-entry phenomena and heat transfer mechanisms.

nicholas0211510
Messages
13
Reaction score
0
How do scientists calculate or estimate the heat of a object in atmospheric re-entry in ° kelvin (the specific formula or formulas if any exist). I'm guessing it has to do with velocity and mass of the object but I'm not sure on the whole process

Thanks in advanced :)
 
Science news on Phys.org
I don't have an answer to your question, but just FYI "reentry" is a term only used for stuff that we sent up and are getting back (whether we like it or not). Meteors have never been here so they are not RE-entering, just entering. Also, I think the heat you are talking about is just what exists at the surface of the object entering the atmosphere. For example, the Space Shuttle ablative tiles got REALLY hot, but the rest of the vehicle didn't. So "meteor heat" isn't quite the right concept, it's more "surface heat of object entering atmosphere".

phinds the NitPicker :smile:
 
  • Like
Likes nicholas0211510
Thanks for some clarification :)
 
Disclaimer: I may not know what I'm talking about. I would appreciate it if someone more knowledgeable than I could correct any errors.

I recall reading somewhere, I have no idea where, that the majority of heat comes from, compression, rather than friction. I would imagine that the heating from friction would pretty well cancel out with how quickly the air would cool it.

If that is correct, you should be able to determine the temperature of the air if you can calculate the pressure in front of the object.
 
nicholas0211510 said:
How do scientists calculate or estimate the heat of a object in atmospheric re-entry in ° kelvin (the specific formula or formulas if any exist). I'm guessing it has to do with velocity and mass of the object but I'm not sure on the whole process

Thanks in advanced :)

You can get a rough estimate by the color of the meteor trail (assuming blackbody radiation and using Wien's law)- by my eye, the color is orange-red, corresponding to about 5000K. The space shuttle materials, during re-entry, had to deal with about 2000K loads
 
Murdock said:
Disclaimer: I may not know what I'm talking about. I would appreciate it if someone more knowledgeable than I could correct any errors.

I recall reading somewhere, I have no idea where, that the majority of heat comes from, compression, rather than friction. I would imagine that the heating from friction would pretty well cancel out with how quickly the air would cool it.

If that is correct, you should be able to determine the temperature of the air if you can calculate the pressure in front of the object.
Stagnation temperature.
Nasa has a brief on it.
http://www.grc.nasa.gov/WWW/BGH/stagtmp.html

The graph gives temperature in degrees Rankine.

The dotted lines for an imperfect gas means that the object( or the air) has to be traveling faster to give the same stagnation temperature, or, at the same Mach number the imperfect gas will give a lower stagnation temperature.

Of course that temperature is only at one small spot where the air and the object are at the same velocity relative to one other, hense the term stagnation.
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
0
Views
1K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K