Calculating Height & Time of a Falling Ball | Physics Problem Solution

  • Thread starter Thread starter Manni
  • Start date Start date
  • Tags Tags
    Ball Falling
Click For Summary

Homework Help Overview

The problem involves a ball dropped from rest, focusing on calculating the height from which it was dropped and the total time of its fall. The context is one-dimensional motion under the influence of gravity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss identifying the type of motion and relevant equations. There is an exploration of how to incorporate the specific condition of covering three-quarters of the distance in the last second of the fall into their reasoning.

Discussion Status

The discussion is ongoing, with participants sharing equations and attempting to clarify how to apply them to the problem. Some guidance has been offered regarding the use of motion equations, but no consensus has been reached on the next steps.

Contextual Notes

Participants note the importance of the "last second" condition and the need to determine the time to fall from the initial height, which remains a point of exploration.

Manni
Messages
42
Reaction score
0
A ball, dropped from rest, covers three-quarters of the distance to the ground in the last second of its fall. a) From what height was the ball dropped? b) What was the total time of the fall?

Hey, I don't know how to approach these types of problems. Help?
 
Physics news on Phys.org
Hi Manni. The approach is nearly always to ask, "What type of motion is it? What formulas apply?" Once you can write a formula for the height as a function of time, you'll be able to apply a bit of math to it and find the answers!
 
It's 1 dimensional motion in the y-direction. As for the equations, there's 2 that I can think of off the top of my head:

Velocity = v(initial) + at
Position = x(initial) + (0.5)[ v(initial) + v ]t

I don't know what to do from there.
 
Position = x(initial) + (0.5)[ v(initial) + v ]t
should be y = yi + Vi*t + ½ a⋅t²

How do we put in
A ball, dropped from rest, covers three-quarters of the distance to the ground in the last second of its fall.
Have to do something with "last second" for starters!
Maybe find the time to fall from height Yi. Then subtract 1 to get the time at the point where it still has 3/4 of the distance to fall.

To find the time to fall, work with the second equation and solve for t.
 

Similar threads

Replies
34
Views
3K
  • · Replies 38 ·
2
Replies
38
Views
4K
Replies
7
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
10
Views
5K
  • · Replies 32 ·
2
Replies
32
Views
4K
Replies
12
Views
1K