Calculating Helium Balloon Volume for 500 kg Payload

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Homework Help Overview

The discussion revolves around calculating the volume of a helium balloon necessary to lift a payload of 500 kg, as well as exploring a related problem involving a balloon's altitude based on various parameters such as weight and air density. The subject area includes buoyancy principles and gas laws.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of buoyancy formulas and the relationship between the volume of helium and the weight of the payload. Questions arise regarding the handling of equations with multiple variables and the interpretation of given values.

Discussion Status

Some participants have offered equations and attempted to clarify the relationships between the variables involved. There is ongoing exploration of the correct approach to solve the problems, with no explicit consensus reached on the methods or outcomes.

Contextual Notes

Participants note confusion regarding the variables and units in the equations, as well as the implications of the payload weight on the calculations. The original poster expresses uncertainty about the formulas provided and their applicability to the problem at hand.

nsw
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I can't seem to figure this simple helium balloon problem out? I would really appreciate some help? Thanks!

Estimate the volume of a helium-filled balloon at STP if it is to lift a payload of 500 kg. The density of air is 1.29 kg/cubic meter and helium has a density of .178 kg/cubic meter.

I think you use a formula like force bouyancy equals density of air times volume times gravity? but not quite sure.
 
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let V : Volume
a= density of air
b= density of He

we have

Code:
 V*a=500*10[sup]3[/sup]+V*b
 
How are you supposed to solve this equation with two unknowns?
 
only V is unknown
 
How do you solve

V(1.29)= 500000+V(0.178)

and is this really your answer?
 
Originally posted by nsw
How do you solve

V(1.29)= 500000+V(0.178)

and is this really your answer?

sorry the units of density are in Kg/m^3 so the equation will be

(1.29-0.178)V=500

V=450 m3
 
Where does the 500 come from?
 
isn't it the weight of the payload
 
Oh Yah! Thanks a Bunch!
 
  • #10
New problem

The values:
Balloon diameter : 100 feet
Balloon weight : 10,000 pounds
Payload weight : 6,000 pounds
Lifting gas : Helium
Air density at ground level : .0625 lbs/cubic foot
Temperature is constant

At what altitude does the balloon fly?

So far I've got:
h = alpha [0.862 - (16,000 lbs/ mass of air)]

I'm not even sure what the variables are, I was given 47 different formulas to determine the answer to this question, none of which are helping whatsoever.
 
Last edited:
  • #11
footos66 said:
The values:
Balloon diameter : 100 feet
Balloon weight : 10,000 pounds
Payload weight : 6,000 pounds
Lifting gas : Helium
Air density at ground level : .0625 lbs/cubic foot
Temperature is constant

At what altitude does the balloon fly?

So far I've got:
h = alpha [0.862 - (16,000 lbs/ mass of air)]

I'm not even sure what the variables are, I was given 47 different formulas to determine the answer to this question, none of which are helping whatsoever.
use bouyancy formula.
 
  • #12
Which is:

mass of air (at Height, h) = [mass of payload+mass of balloon+mass of lifting gas]

is that the right one?
 

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