Calculating Image Size of Dropped Ball from a Concave Mirror

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SUMMARY

The discussion focuses on calculating the image size of a 7 cm diameter styrofoam ball dropped from a height of 3 meters above a concave mirror with a focal length of 1 meter. The key equation used is the mirror formula, 1/f = 1/Di + 1/Do, which relates the object distance (Do) and image distance (Di). To determine when the image size equals the object size, participants are advised to utilize the magnification formula, M, which relates image size to object size and image distance to object distance. Kinematics is also suggested to calculate the time it takes for the ball to fall to the required height.

PREREQUISITES
  • Understanding of concave mirrors and their focal lengths
  • Familiarity with the mirror equation: 1/f = 1/Di + 1/Do
  • Knowledge of magnification and its calculation
  • Basic kinematics for calculating falling objects
NEXT STEPS
  • Study the concept of magnification in optics
  • Learn how to apply the mirror equation in practical scenarios
  • Explore kinematic equations for free-falling objects
  • Review examples of image formation by concave mirrors
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Students studying physics, particularly those focusing on optics and kinematics, as well as educators looking for practical examples of image formation using concave mirrors.

patton_223
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Homework Statement


"a concave mirror is placed horizontally on the ground with a focal length of 1 meter, a boy sitting on a tree above the mirror drops a 7cm diameter styrofoam ball right over the mirror 3 meters high, determine when the image will be the same size of the ball"


Homework Equations



1/f= 1/Di + 1/Do

The Attempt at a Solution



i've found the distance of image when the ball is at 3M but i really don't know what to do from there. i honestly think there is no way of finding it, i think there's something missing (i may be wrong though lol)
 
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Hello patton_223,

Welcome to Physics Forums!
patton_223 said:
i've found the distance of image when the ball is at 3M but i really don't know what to do from there. i honestly think there is no way of finding it, i think there's something missing (i may be wrong though lol)
Look up in your textbook/coursework about magnification (usually expressed with the variable M). You can express M as a ratio of image to object distances, and you can also express it in terms of a ratio of image size to object size. Combining equations and using substitution (including your 1/f = 1/Do - 1/Di formula), you can solve for the distance above the mirror.

By the way, "3 m high" means that the ball is 3 m above the mirror when time t = 0. Once you find the distance above the mirror where the image and object sizes are equal, use kinematics to find the time it takes for the ball to fall to that height.
 

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