Calculating Impedance Using Capacitive Reactance

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PeachBanana
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Homework Statement



A 29kΩ resistor is in series with a 62mH inductor and an ac source. Calculate the impedance of the circuit if the source frequency is 80Hz .

Homework Equations



XL = ωL
Z = [(R^2 + (XL - XC)^2)] ^ 1/2


The Attempt at a Solution



R = 29,000 Ω

XL = 0.062 H (2∏ * 80 Hz)
XL = 31.16 Ω

I'm having difficulty figuring out how to find XC. XC = 1 / ωC but what is "C?"
 
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PeachBanana said:

Homework Statement



A 29kΩ resistor is in series with a 62mH inductor and an ac source. Calculate the impedance of the circuit if the source frequency is 80Hz .

Homework Equations



XL = ωL
Z = [(R^2 + (XL - XC)^2)] ^ 1/2

The Attempt at a Solution



R = 29,000 Ω

XL = 0.062 H (2∏ * 80 Hz)
XL = 31.16 Ω

I'm having difficulty figuring out how to find XC. XC = 1 / ωC but what is "C?"
Your formula for Z applies to RLC circuits. You have an RL circuit. Do you know how that formula for Z was derived? It was probably using a phasor diagram. If you understand the derivation, it's pretty easy to see what you need to do.
 
Was the formula for "Z" derived using the Pythagorean theorem? If so, I still do not see the connection to capacitance.
 
It looks as if it uses the following relations:

Vrms = Irms * Z
Vnaught = InaughtZ

The book also shows a phasor diagram where Vnaught is the sum vector and acts as the hypotenuse of the triangle.
 
The triangle comes from a phasor diagram. I'm attaching an image made in paint of the one I see in the textbook. It's a tad messy, but it is readable.
 

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Are the voltages being added together to find the peak voltage source, Vnaught?
Is Vc subtracted from Vl because Vc lags the current by 90°?
 
PeachBanana said:
Are the voltages being added together to find the peak voltage source, Vnaught?
Yes, it's Kirchoff's voltage law applied to the elements in series.

Is Vc subtracted from Vl because Vc lags the current by 90°?
And because VL leads the current by 90°. The two phasors point in opposite directions, so when you add them vector-wise, you subtract their magnitudes.

So back to your original problem, if you follow the same analysis, what do you get for the impedance?
 
Since this is an RL circuit then

Z = [(R^2 + XL^2)]^1/2