# Working out the impedance of a network query

## Homework Statement

Calculate the J notation impedance of the network

We have an inductor in series with a resistor and both in parallel with a capacitor.

## The Attempt at a Solution

i believe it is true that if I was to say: if I have an inductor in parallel with a capacitor then:

Product/Sum = XL*-XC/XL-XC

This would then go like (XL*-XC)(XL+XC) / (XL-XC)(XL+XC) because of complex conjugate.

If this then was as above in the original setup:

We have an inductor in series with a resistor and both in parallel with a capacitor.

then could you say:

(R+JXL)*(-JXC) / (R+JXL-JXC) or (R+J(XL-XC))

Could I then say by complex conjugate:

((R+JXL)*(-JXC)) (R-J(XL-XC)) / (R+J(XL-XC)) (R-J(XL-XC))

Thanks for any help in advance, it is much appreciated.

Last edited:

ehild
Homework Helper
We have an inductor in series with a resistor and both in parallel with a capacitor.

then could you say:

(R+JXL)*(-JXC) / (R+JXL-JXC) or (R+J(XL-XC))

Could I then say by complex conjugate:

((R+JXL)*(-JXC)) (R-J(XL-XC)) / (R+J(XL-XC)) (R-J(XL-XC))

It looks correct.

ehild