Working out the impedance of a network query

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SUMMARY

The discussion focuses on calculating the J notation impedance of a network consisting of an inductor in series with a resistor, both in parallel with a capacitor. The user proposes a formula using the relationship between the reactance of the inductor (XL) and the capacitor (XC) to derive the impedance. The final expression involves complex conjugates and confirms the validity of the approach to calculate the impedance accurately.

PREREQUISITES
  • Understanding of complex numbers and their conjugates
  • Knowledge of electrical components: inductors, resistors, and capacitors
  • Familiarity with impedance calculations in AC circuits
  • Basic proficiency in using J notation for complex impedance
NEXT STEPS
  • Study the principles of AC circuit analysis
  • Learn about complex impedance and its applications in electrical engineering
  • Explore the use of complex conjugates in circuit calculations
  • Review series and parallel circuit configurations for inductors and capacitors
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing AC circuits and impedance calculations.

lubo
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Homework Statement



Calculate the J notation impedance of the network

We have an inductor in series with a resistor and both in parallel with a capacitor.


Homework Equations





The Attempt at a Solution


i believe it is true that if I was to say: if I have an inductor in parallel with a capacitor then:

Product/Sum = XL*-XC/XL-XC

This would then go like (XL*-XC)(XL+XC) / (XL-XC)(XL+XC) because of complex conjugate.

If this then was as above in the original setup:

We have an inductor in series with a resistor and both in parallel with a capacitor.

then could you say:

(R+JXL)*(-JXC) / (R+JXL-JXC) or (R+J(XL-XC))

Could I then say by complex conjugate:

((R+JXL)*(-JXC)) (R-J(XL-XC)) / (R+J(XL-XC)) (R-J(XL-XC))

Thanks for any help in advance, it is much appreciated.
 
Last edited:
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lubo said:
We have an inductor in series with a resistor and both in parallel with a capacitor.

then could you say:

(R+JXL)*(-JXC) / (R+JXL-JXC) or (R+J(XL-XC))

Could I then say by complex conjugate:

((R+JXL)*(-JXC)) (R-J(XL-XC)) / (R+J(XL-XC)) (R-J(XL-XC))

It looks correct.


ehild
 

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