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## Homework Statement

Calculate the J notation impedance of the network

We have an inductor in series with a resistor and both in parallel with a capacitor.

## Homework Equations

## The Attempt at a Solution

i believe it is true that if I was to say: if I have an inductor in parallel with a capacitor then:

Product/Sum = XL*-XC

**/**XL-XC

This would then go like (XL*-XC)(XL+XC)

**/**(XL-XC)(XL+XC) because of complex conjugate.

If this then was as above in the original setup:

We have an inductor in series with a resistor and both in parallel with a capacitor.

then could you say:

(R+JXL)*(-JXC)

**/**(R+JXL-JXC) or (R+J(XL-XC))

Could I then say by complex conjugate:

((R+JXL)*(-JXC)) (R-J(XL-XC))

**/**(R+J(XL-XC)) (R-J(XL-XC))

Thanks for any help in advance, it is much appreciated.

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