1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Working out the impedance of a network query

  1. Oct 28, 2011 #1
    1. The problem statement, all variables and given/known data

    Calculate the J notation impedance of the network

    We have an inductor in series with a resistor and both in parallel with a capacitor.


    2. Relevant equations



    3. The attempt at a solution
    i believe it is true that if I was to say: if I have an inductor in parallel with a capacitor then:

    Product/Sum = XL*-XC/XL-XC

    This would then go like (XL*-XC)(XL+XC) / (XL-XC)(XL+XC) because of complex conjugate.

    If this then was as above in the original setup:

    We have an inductor in series with a resistor and both in parallel with a capacitor.

    then could you say:

    (R+JXL)*(-JXC) / (R+JXL-JXC) or (R+J(XL-XC))

    Could I then say by complex conjugate:

    ((R+JXL)*(-JXC)) (R-J(XL-XC)) / (R+J(XL-XC)) (R-J(XL-XC))

    Thanks for any help in advance, it is much appreciated.
     
    Last edited: Oct 28, 2011
  2. jcsd
  3. Oct 29, 2011 #2

    ehild

    User Avatar
    Homework Helper
    Gold Member

    It looks correct.


    ehild
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Working out the impedance of a network query
Loading...