Calculating Initial Speed for Successful Projectile Shot: Basketball Example

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SUMMARY

The discussion focuses on calculating the initial speed required for a basketball shot to successfully land in a hoop 3.0 meters high, shot at an angle of 55 degrees. The equations derived include horizontal and vertical motion components: Vx = vcos(55) and Vy = vsin(55) - gt. The user ultimately determined that the time of flight (t) is 0.8 seconds and the initial speed (v) is 9.4 m/s after solving the simultaneous equations derived from the projectile motion equations.

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A basketball player shoots a ball at an angle of 55o into a hoop and lands in the net, which is 3.0m off the ground. Calculate the initial speed of the ball for this fould shot to be successful.

I did some vector integration and then isolated each of the components:

Vx= vcos55
Vy= vsin55 - gt
sx= vcos55t
sy= vsin55t - gt2/2 + 2.1

When

sy= vsin55t - gt2/2 + 2.1 = 3
sx= vcos55t = 4.3

However, even after some manipulating, there are two variables and I can't isolate any of them. Or maybe I am just missing something?
 
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Hello,

you got these two equations:
sy= vsin55t - gt2/2 + 2.1 = 3
sx= vcos55t = 4.3

can you from sx express t in terms of v and then put this in sy?
 
Hey, first off you need to approach the problem "more simply" some trig will hopefully give the horizontal distance to be 4.3m (what you've said, not right for the vales you've given it would be 2.1m. I am assuming typo in the given info) and then you have your component velocitys. From that s_i=4.3=vcos(55)t+0.5*0t^2 =v*cos(55)t and s_j=3=vsin(55)t+0.5*9.81t^2. you now have a system of simultaneous equations, solve them. (FYI i got t=0.8s and v = 9.4m/s) Please let me know if this was helpful(or even correct) thanks.
 
Last edited:

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