I'm trying to calculate insulation thickness for a foundry, and can't figure it out after spending a few hours searching.(adsbygoogle = window.adsbygoogle || []).push({});

Refractory: Kast-O-Lite

Material Required: 1.44g/cm^3

Thermal Conductivity: 0.65 W/m*C

Maximum inside temperature is 1648*C

I figured there would be a minimum of 10,440 BTU/3057 Watts Required to melt 4.16L of Aluminum

Inside Dimensions "Empty Space" would be 16cm Diameter x 23cm Tall

Outside Dimensions: 31cm Diameter x 44.5cm Tall

The closest thing I found to this would be Insulation thickness calculation for a pipe - EngCyclopedia

However, I cannot figure out how to determine r2

Q=2*pi*k*N*((T1-T2)/ln(r2/r1)

T1=50*C

T2=1648*C

r1=0.1524m

r2=??

k=0.65 (W/m*C)

N=0.2032m

Q=2*pi*0.65*0.2032

Q=0.829883115*(-5198)/(ln(r2/0.1524)

Can anyone help me out, or point me in the right direction?

They say "Rule of Thumb" is 4inches/10cm of refractory. If I could just figure out what the outside temperature of that would be I think it would be helpful.

Thank you very much!

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# Calculating Insulation Thickness

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