How to Calculate Heat Loss in an Aluminum Pipe with Fluid Flow?

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SUMMARY

The discussion focuses on calculating heat loss in an aluminum pipe with fluid flow, specifically a 1-meter long pipe with an outer radius of 3.5 cm and an inner radius of 3 cm, carrying fluid at 30 °C while the surrounding temperature is 20 °C. The heat conductivity of aluminum is given as 210 W/mK. The correct formula for heat loss is Q = XS(T2-T1) * τ / L, where L represents the thickness of the pipe. The initial calculation yielded approximately 0.85 GJ, while the correct value is 0.88 GJ, indicating a need for accurate thickness and surface area calculations.

PREREQUISITES
  • Understanding of heat transfer principles, specifically conduction.
  • Familiarity with the formula for calculating heat loss in cylindrical objects.
  • Knowledge of material properties, particularly thermal conductivity.
  • Basic algebra for manipulating equations and solving for unknowns.
NEXT STEPS
  • Review the derivation of the heat conduction equation for cylindrical geometries.
  • Study the impact of thermal conductivity on heat transfer rates in different materials.
  • Learn about calculating surface area for cylindrical objects to improve accuracy in heat loss calculations.
  • Explore resources on heat transfer theory, particularly conduction, to solidify foundational knowledge.
USEFUL FOR

Students in engineering or physics, professionals involved in thermal management, and anyone interested in understanding heat transfer in materials, particularly in piping systems.

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Homework Statement


Through a pipe made of aluminum, length of 1m which outer radius is r1=3,5 cm and inner radius is r2=3 cm flows a fluid with temperature of t1= 30 °C. How much heat does get lost through the walls of the pipe, in \tau=3h if the temperature around the pipe is 20 °C. Heat conductivity of aluminum is \chi=210 W/mK

Homework Equations



Heat lost: Q=XS(T2-T1)*\tau/L

where L is thickness of the pipe.

The Attempt at a Solution



Now I get the roughly 0,85 GJ.
But the solution says its 0,88 GJ and that a bit difference when you are talking about GIGA Jules.

I think I got the thickness of the pipe wrong and surface area through which heat is being transferred.

Can anybody help me here?
 
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Close the thread, I got the formula wrong. Btw can anybody here give me a good link with good theory with conduction of heat?
 

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