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I'm working on this problem and I'd like to know how to find the invariant mass using just the lab-frame momentum and rest mass.

I've found a lot of equations that deal with E, and I'm not completely sure what that is either.

Thanks

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In summary, the conversation discusses finding the invariant mass using lab-frame momentum and rest mass. The equation E^2 = m0^2c^4 + (pc)^2 is suggested as a solution, with E representing total inertial energy. The total inertial energy is defined as the sum of a particle's rest mass and kinetic energy.

- #1

- 9

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I'm working on this problem and I'd like to know how to find the invariant mass using just the lab-frame momentum and rest mass.

I've found a lot of equations that deal with E, and I'm not completely sure what that is either.

Thanks

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- #2

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You have to tell us "this problem".

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Thanks

- #4

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iloveflickr said:

Thanks

This really belongs in one of the Homework forums:

https://www.physicsforums.com/forumdisplay.php?f=152

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So here's what I have so far...

E* = (Ep* + En*),

where

Ep* = Mp + Pe

En* = Mn

Pe = momentum of electron in lab frame

Ep* = energy of proton in CM frame

En* = energy of neutron in CM frame

Mn/Mp = mass of neutron/proton

Is E* = Invariant mass? If so, I've got this problem done.

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iloveflickr said:

I'm working on this problem and I'd like to know how to find the invariant mass using just the lab-frame momentum and rest mass.

I've found a lot of equations that deal with E, and I'm not completely sure what that is either.

Thanks

As measured in an inertial frame of reference - If m

E^2 = m

Pete

Last edited:

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pmb_phy said:As measured in an inertial frame of reference - If m_{0}= invariant mass of system, p = total momentum of system and E = total inertial energy of the system then

E^2 = m_{0}^{2}c^{4}+(pc)^{2}. Simply solve for the invariant mass m_{0}of the system and you have you're answer.

Pete

Thanks for your response. I found that exact equation in many texts and I haven't a clue what the total inertial energy of the system is.

In my particular problem, would it be E = KE(proton) + Mass(proton) + Mass(neutron)?

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iloveflickr said:Thanks for your response. I found that exact equation in many texts and I haven't a clue what the total inertial energy of the system is.

In my particular problem, would it be E = KE(proton) + Mass(proton) + Mass(neutron)?

The

E = K + E

W = E + V

Best wishes

Pete

- #9

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Thanks much.

The formula for calculating invariant mass using momentum and rest mass is given by **m _{0} = √(E^{2} - p^{2}c^{2})/c^{2}**, where m

Invariant mass is important in particle physics because it is a fundamental property of particles that remains constant regardless of the frame of reference. It allows physicists to study and classify particles based on their invariant mass, providing valuable insights into the nature of matter and energy.

Momentum and invariant mass are related through the equation **p = m _{0}γv**, where p is the momentum, m

No, invariant mass cannot be negative. Invariant mass is a measure of the energy and momentum of a particle, and both energy and momentum are always positive quantities. Therefore, the square root in the formula for calculating invariant mass will always yield a positive value.

The concept of relativistic mass is related to invariant mass in that both are measures of a particle's energy and momentum. However, relativistic mass is a frame-dependent quantity, meaning it changes depending on the observer's frame of reference, while invariant mass remains constant. Invariant mass is considered a more fundamental and useful concept in particle physics.

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