Calculating Jupiter's Mass from Orbital Data

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Homework Help Overview

The discussion revolves around calculating the mass of Jupiter using the orbital data of its satellite Io, specifically its orbital period and radius. Participants are attempting to apply Kepler's laws and gravitational equations to derive the mass from the given parameters.

Discussion Character

  • Mathematical reasoning, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are using the formula T^2 = (4π^2/(G*M)) * R^3 to relate the orbital period and radius to the mass of Jupiter. There are questions about the accuracy of calculations and the correct interpretation of the formula, including the handling of constants and units.

Discussion Status

The discussion is ongoing, with participants sharing their calculations and questioning each other's methods. Some have provided corrections regarding the use of constants and units, while others express confusion about their results. There is no clear consensus yet, as multiple interpretations and calculations are being explored.

Contextual Notes

Participants have noted issues with unit conversions and the proper application of the gravitational constant. There is also a mention of formatting preferences for mathematical expressions, indicating a focus on clarity in communication.

BoldKnight399
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Io, a satellite of Jupiter, has an orbital period of 1.43 days and an orbital radius of 4.35X10^5 km. From this data, determine the mass of Jupiter.

So step one: I cried.
then I tried to use the equation:
T^2=4(pi)^2/(GXMj) X R^3
thus
(123552)^2= (39.478)/(6.672X10^-11)(Mj) X (4.34X10^5)^3

35161.29=(39.478)/(6.672X10^-11)(Mj) X (8.17465X10^16)

Mj=1.3756X10^24

Apparently I was wrong...
Anyone have any ideas what I did to mess this up?
 
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Hi BoldKnight399! :smile:

(please don't use X for "times" … either use * or nothing … oh and have a pi: π and try using the X2 tag just above the Reply box :wink:)
BoldKnight399 said:
(123552)^2= (39.478)/(6.672X10^-11)(Mj) X (4.34X10^5)^3

35161.29=(39.478)/(6.672X10^-11)(Mj) X (8.17465X10^16)

I'm not sure what your fomula is :redface:, but anyway where did 35161.29 come from (did you take a square-root instead)?
 
I just used the formula:
T^2=(4(Pi)^2/G*M)*R^3

and i have no idea what I did to get 35161.29 in addition, what do you mean about having pi=n?
 
ok so I tried it then having the time correctly squared:
(1.526X10^10)=(39.478/(6.673*10^-11)(M)) * (8.321*10^16)
and i got that the Mass of Jupiter was 3.19*10^18

that was wrong. I don't understand what I am doing wrong
 
(please use the X2 tag just above the Reply box)

Try using m instead of km ! :wink:

(oh, and it wasn't n, it was π :biggrin:)
 
alright, so it became:
(1.526X10^10)=(39.478/(6.673*10^-11)(M)) * (8.321*10^19)
M=3.2259*10^21

still wrong. I thought I had everything right.
 
erm :redface:

cubed? :smile:
 
wow...I am not having a good physics day I guess. Thank you so much. I got:
3.16*10^27 and that was right.
 

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