How to Calculate the Mass of Jupiter Using Orbital Data

Click For Summary

Homework Help Overview

The discussion revolves around calculating the mass of Jupiter using the orbital data of its moon Io, specifically its orbital period and radius. The problem is situated within the context of gravitational physics and orbital mechanics.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of Kepler's third law and the rearrangement of the formula to solve for the mass of Jupiter. Questions arise regarding unit conversions and the accuracy of calculations.

Discussion Status

Some participants have provided guidance on the formula to use and noted potential errors in calculations. There is an acknowledgment of a misunderstanding regarding unit conversions, and one participant has indicated that they resolved their issue after reviewing their calculations.

Contextual Notes

There is a mention of converting kilometers to meters, which is crucial for the calculations. Additionally, the gravitational constant and the specific formula used are discussed, highlighting the importance of accurate input values in the calculations.

bona0002
Messages
14
Reaction score
0
Hi guys,

I'm not sure if I'm going about this the correct way, but it seems to be the only one that makes sense right now. The problem reads: Io, a satellite of Jupiter, has an orbital period of 1.77 days and an orbital radius of 4.22E5 km. From these data, determine the mass of Jupiter.

So, with that in mind, the equation that pops out at me is T^2 = (4*pi^2)(a^3)/(G*M_big_). Now, assuming that M_big_ is the size of jupiter, one can solve for M_big_: M_big_ = (4*pi^2)(a^3)/(T^2*G). Before substituition, I convered 1.77 days into 1.53E5 seconds. Then, I substituted: M_big_ = ((4*pi^2)*(4.22E5km)^3)/((1.53E5)^2)*(6.67E-11) = 1.07E7 kg.

So, is my process right and I'm simply punching it in wrong, or is it that my logic is flawed?

Thanks!
 
Physics news on Phys.org
bona0002 said:
Hi guys,

I'm not sure if I'm going about this the correct way, but it seems to be the only one that makes sense right now. The problem reads: Io, a satellite of Jupiter, has an orbital period of 1.77 days and an orbital radius of 4.22E5 km. From these data, determine the mass of Jupiter.

So, with that in mind, the equation that pops out at me is T^2 = (4*pi^2)(a^3)/(G*M_big_). Now, assuming that M_big_ is the size of jupiter, one can solve for M_big_: M_big_ = (4*pi^2)(a^3)/(T^2*G). Before substituition, I convered 1.77 days into 1.53E5 seconds. Then, I substituted: M_big_ = ((4*pi^2)*(4.22E5km)^3)/((1.53E5)^2)*(6.67E-11) = 1.07E7 kg.

So, is my process right and I'm simply punching it in wrong, or is it that my logic is flawed?

Thanks!

Change km to m.
 
rude man said:
Change km to m.

I did. The answer I get then is 1.07E10, which is supposedly incorrect.
 
bona0002 said:
I did. The answer I get then is 1.07E10, which is supposedly incorrect.

From what I can see, the formula you want is \frac{2πr}{T}=\sqrt{\frac{GM}{r}}

With M being the mass of Jupiter, G being the gravitational constant, r being the radius from the centre of Jupiter, and T being the period.

Good luck :)
 
Alright, figured it out. Turns out I had the process down just fine, but just that when punching in the numbers on my calculator, I forgot to cube a. Thanks for the help guys!
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
27K
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
7K
Replies
6
Views
4K
Replies
8
Views
2K