Calculating Kinetic Energy and Force Required to Stop a Car

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Homework Help Overview

The discussion revolves around calculating the kinetic energy of a car and determining the force required to stop it within a specified time frame. The subject area includes concepts from mechanics, specifically kinetic energy and Newton's laws of motion.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between kinetic energy and force, with one participant attempting to calculate the force using an equation involving energy and time. Others question the deceleration needed to stop the car and the corresponding net force required. There is discussion about the application of Newton's second law (F=ma) and how to determine the acceleration based on the change in speed over time.

Discussion Status

The conversation is active, with participants sharing their calculations and reasoning. Some guidance has been provided regarding the correct interpretation of acceleration and its role in calculating force. Multiple interpretations of the problem are being explored, particularly regarding the signs of force and acceleration.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information available for discussion. There is an emphasis on understanding the relationships between the variables involved in the problem.

pat666
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Homework Statement


A car of mass 2 (metric) tonnes is traveling at 20m/s. caculate its kinetic energy (can and have done) and the force required to stop it in 10 s.

Homework Equations


The Attempt at a Solution


I have found the KE = 4 *10^5 but i can't figure out how to calculate the force required to stop it in 10s. I think the equation for this mite be E/t=FV

The answer is 4*10^3N
 
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To change it speed from 20m/s to 0m/s requires a deceleration of how much? What net force is required to produce this deceleration (what law relates net acceleration of a body to the net force)?
 
so is it F=ma
that would give F=2000*-20
which = 4*10^4 not 10^3
also the force is positive but i suppose you just swap it because it is in the opposite direction to the original?? Also what then puts the 10s into the equation??
 
pat666 said:
so is it F=ma
that would give F=2000*-20
which = 4*10^4 not 10^3
also the force is positive but i suppose you just swap it because it is in the opposite direction to the original??

Yes use F=ma, but think about what value of 'a' you have used. a, acceleration, measures the rate at which speed is changing. If the speed changes from 20 to 0 over a period of 10 seconds, what is the acceleration?
 
ok i think i get it now the acceleration should = 20-0/10
which = 2
so F= 2000*2
=4*10^3
thankyou so much
This website is ausome...
 
pat666 said:
ok i think i get it now the acceleration should = 20-0/10
which = 2
so F= 2000*2
=4*10^3
thankyou so much
This website is ausome...

No problems :smile: And yes this website is the best haha.
 

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