Calculating Linear Charge Density of a Cylinder

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The discussion focuses on calculating the linear charge density of an infinitely long cylinder with a given volume charge density. The linear charge density is derived from the volume charge density by multiplying it with the cylinder's cross-sectional area, leading to the expression λ = πR²ρ₀(α - r/β). There is a concern that this method only applies if the charge density is uniform across the cylinder's cross-section. The conversation also highlights the need to use Gauss's Law for determining the electric field in parts b and c, emphasizing the importance of understanding the charge distribution. The participant expresses uncertainty about proceeding with parts b and c without confidence in part a.
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Homework Statement
An infinitely long cylinder carries a charge density throughout its volume given by:
𝜌(𝑟) = 𝜌0 (𝛼 − 𝑟 /𝛽)
where 𝑟 is the radial distance from its central axis and 𝜌0, 𝛼, and 𝛽 are positive constants. The radius of the cylinder is 𝑅 beyond which the charge density is zero.
(a) Obtain an expression for the linear charge density of the cylinder.
(b) Obtain expressions for the electric field inside (𝑟 < 𝑅) and outside (𝑟 > 𝑅) the cylinder.
(c) Taking 𝑉(𝑅) = 0 as the reference, get the potential of the cylinder for points inside and outside the cylinder.
Relevant Equations
Linear charge density, Gauss's Law
For part a:

I know that linear charge density is the amount of charge per unit length, and we are given the volume charge density. Since we are given the volume, we can obtain the length by multiplying the volume by the cross sectional area, so C/m^3 * m^2 = C/m. The cross sectional area of a cylinder is A= πR^2, so we can get the linear charge density by solving for λ=𝜌A, and multiply our area by our initial equation to get:

λ = πR^2 𝜌0 (𝛼 − 𝑟/𝛽)

I haven't began part b or c yet, because I am not confident in part a. I do think that in both cases, for r>R (outside of the cylinder), that the electric field and potential would be zero, because R is beyond where the charge density is zero.

I also know to use Gauss's Law for part b, and integration for part c, but am not entirely sure where to begin.

Thank you!
 
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chichiba said:
Homework Statement:: An infinitely long cylinder carries a charge density throughout its volume given by:
𝜌(𝑟) = 𝜌0 (𝛼 − 𝑟 /𝛽)
where 𝑟 is the radial distance from its central axis and 𝜌0, 𝛼, and 𝛽 are positive constants. The radius of the cylinder is 𝑅 beyond which the charge density is zero.
(a) Obtain an expression for the linear charge density of the cylinder.
(b) Obtain expressions for the electric field inside (𝑟 < 𝑅) and outside (𝑟 > 𝑅) the cylinder.
(c) Taking 𝑉(𝑅) = 0 as the reference, get the potential of the cylinder for points inside and outside the cylinder.
Relevant Equations:: Linear charge density, Gauss's Law

For part a:

I know that linear charge density is the amount of charge per unit length, and we are given the volume charge density. Since we are given the volume, we can obtain the length by multiplying the volume by the cross sectional area, so C/m^3 * m^2 = C/m. The cross sectional area of a cylinder is A= πR^2, so we can get the linear charge density by solving for λ=𝜌A, and multiply our area by our initial equation to get:

λ = πR^2 𝜌0 (𝛼 − 𝑟/𝛽)
Your method for finding ##\lambda## will only work if ##\rho## is uniform across a cross section of the cylinder.

Consider a section of the cylinder of infinitesimal length ##dx## and let ##dQ## be the total charge contained within this section. ##\lambda = dQ/dx##.

1674847382907.png


Can you use ##\rho(r)## to find an expression for ##dQ##?
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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