Calculating Linear Charge Density of a Cylinder

Click For Summary
SUMMARY

The discussion focuses on calculating the linear charge density of an infinitely long cylinder with a volume charge density defined by ๐œŒ(๐‘Ÿ) = ๐œŒ0 (๐›ผ โˆ’ ๐‘Ÿ/๐›ฝ). The linear charge density is derived using the formula ฮป = ฯ€Rยฒ๐œŒ0(๐›ผ โˆ’ ๐‘Ÿ/๐›ฝ), where R is the radius of the cylinder. The participants also discuss the implications of Gauss's Law for determining the electric field inside and outside the cylinder, noting that the electric field and potential are zero for r > R. The conversation highlights the importance of uniform charge distribution for accurate calculations.

PREREQUISITES
  • Understanding of linear charge density and volume charge density
  • Familiarity with Gauss's Law and its applications
  • Knowledge of integration techniques for calculating electric potential
  • Basic geometry of cylinders, including cross-sectional area calculations
NEXT STEPS
  • Learn how to apply Gauss's Law to different charge distributions
  • Study the derivation of electric fields from charge densities
  • Explore integration methods for calculating electric potential
  • Investigate the effects of non-uniform charge distributions on electric fields
USEFUL FOR

Students and professionals in physics, particularly those studying electromagnetism, electrical engineering, or anyone involved in calculating electric fields and potentials in charged cylindrical systems.

chichiba
Messages
1
Reaction score
0
Homework Statement
An infinitely long cylinder carries a charge density throughout its volume given by:
๐œŒ(๐‘Ÿ) = ๐œŒ0 (๐›ผ โˆ’ ๐‘Ÿ /๐›ฝ)
where ๐‘Ÿ is the radial distance from its central axis and ๐œŒ0, ๐›ผ, and ๐›ฝ are positive constants. The radius of the cylinder is ๐‘… beyond which the charge density is zero.
(a) Obtain an expression for the linear charge density of the cylinder.
(b) Obtain expressions for the electric field inside (๐‘Ÿ < ๐‘…) and outside (๐‘Ÿ > ๐‘…) the cylinder.
(c) Taking ๐‘‰(๐‘…) = 0 as the reference, get the potential of the cylinder for points inside and outside the cylinder.
Relevant Equations
Linear charge density, Gauss's Law
For part a:

I know that linear charge density is the amount of charge per unit length, and we are given the volume charge density. Since we are given the volume, we can obtain the length by multiplying the volume by the cross sectional area, so C/m^3 * m^2 = C/m. The cross sectional area of a cylinder is A= ฯ€R^2, so we can get the linear charge density by solving for ฮป=๐œŒA, and multiply our area by our initial equation to get:

ฮป = ฯ€R^2 ๐œŒ0 (๐›ผ โˆ’ ๐‘Ÿ/๐›ฝ)

I haven't began part b or c yet, because I am not confident in part a. I do think that in both cases, for r>R (outside of the cylinder), that the electric field and potential would be zero, because R is beyond where the charge density is zero.

I also know to use Gauss's Law for part b, and integration for part c, but am not entirely sure where to begin.

Thank you!
 
Physics news on Phys.org
chichiba said:
Homework Statement:: An infinitely long cylinder carries a charge density throughout its volume given by:
๐œŒ(๐‘Ÿ) = ๐œŒ0 (๐›ผ โˆ’ ๐‘Ÿ /๐›ฝ)
where ๐‘Ÿ is the radial distance from its central axis and ๐œŒ0, ๐›ผ, and ๐›ฝ are positive constants. The radius of the cylinder is ๐‘… beyond which the charge density is zero.
(a) Obtain an expression for the linear charge density of the cylinder.
(b) Obtain expressions for the electric field inside (๐‘Ÿ < ๐‘…) and outside (๐‘Ÿ > ๐‘…) the cylinder.
(c) Taking ๐‘‰(๐‘…) = 0 as the reference, get the potential of the cylinder for points inside and outside the cylinder.
Relevant Equations:: Linear charge density, Gauss's Law

For part a:

I know that linear charge density is the amount of charge per unit length, and we are given the volume charge density. Since we are given the volume, we can obtain the length by multiplying the volume by the cross sectional area, so C/m^3 * m^2 = C/m. The cross sectional area of a cylinder is A= ฯ€R^2, so we can get the linear charge density by solving for ฮป=๐œŒA, and multiply our area by our initial equation to get:

ฮป = ฯ€R^2 ๐œŒ0 (๐›ผ โˆ’ ๐‘Ÿ/๐›ฝ)
Your method for finding ##\lambda## will only work if ##\rho## is uniform across a cross section of the cylinder.

Consider a section of the cylinder of infinitesimal length ##dx## and let ##dQ## be the total charge contained within this section. ##\lambda = dQ/dx##.

1674847382907.png


Can you use ##\rho(r)## to find an expression for ##dQ##?
 

Similar threads

  • ยท Replies 10 ยท
Replies
10
Views
2K
Replies
6
Views
1K
  • ยท Replies 4 ยท
Replies
4
Views
1K
  • ยท Replies 26 ยท
Replies
26
Views
3K
  • ยท Replies 4 ยท
Replies
4
Views
6K
  • ยท Replies 1 ยท
Replies
1
Views
2K
  • ยท Replies 11 ยท
Replies
11
Views
1K
  • ยท Replies 11 ยท
Replies
11
Views
2K
  • ยท Replies 4 ยท
Replies
4
Views
2K
  • ยท Replies 9 ยท
Replies
9
Views
862