Calculating Magnetic Field Outside Toroidal Solenoid

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SUMMARY

The discussion focuses on calculating the magnetic field outside a toroidal solenoid, specifically addressing magnetic field leakage. It is established that the magnetic field \(\vec{B}\) inside the solenoid is perpendicular to the plane of each coil and is effectively zero outside the solenoid. To compute the magnetic field, users are advised to apply Ampere's Law, represented by the equation \(\int B \cdot d\mathcal{l} = \mu I\), which relates the total current enclosed by a closed loop to the line integral of the magnetic field around that loop.

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  • Understanding of Ampere's Law
  • Familiarity with magnetic field concepts
  • Knowledge of toroidal solenoid geometry
  • Basic calculus for line integrals
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  • Explore magnetic field calculations for various solenoid shapes
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LordBerkley
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If I have a solenoid in the shape of a toroid (i.e. solenoid joined end to end) the magnetic field produced by the flow of charge will produce a concentrated magnetic field within the coil.

How would I go about calculating the size of the magnetic field outside of the coil due to magnetic field leakage?

Any advice much appreciated.

LB
 
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LordBerkley said:
If I have a solenoid in the shape of a toroid (i.e. solenoid joined end to end) the magnetic field produced by the flow of charge will produce a concentrated magnetic field within the coil.

How would I go about calculating the size of the magnetic field outside of the coil due to magnetic field leakage?

Any advice much appreciated.

LB

I think that a good approximation would be to assume that the magnetic field \vec{B} inside the soldenoid is directed perpendicular to the plane of each coil and is zero outside of the solenoid. Then you can use Ampere's law to compute it:

\int B \cdot d\mathcal{l} = \mu I

The meaning of that equation is that if you imagine drawing a closed loop that encloses a bunch of wires, then the total current enclosed by the loop is equal to the line integral of B around the loop.
 

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