Calculating Magnitude of Force F2 on Mass M

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SUMMARY

The problem involves calculating the magnitude of force F2 acting on a mass M of 6.0 kg, given force F1 as 7.0i + 5.0j + 6.0k N and acceleration a as 1.0i + 3.0j + 3.0k m/s². To find F2, apply Newton's second law, F = ma, which leads to F2 = F1 + ma. By calculating the resultant force from the acceleration, F2 can be determined as 12.0i + 24.0j + 18.0k N. The magnitude of F2 is then calculated using the formula √(x² + y² + z²).

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  • Understanding of Newton's second law of motion
  • Vector addition and subtraction
  • Basic knowledge of force and acceleration units
  • Familiarity with calculating vector magnitudes
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  • Learn how to apply Newton's second law in various scenarios
  • Explore the calculation of vector magnitudes in three-dimensional space
  • Practice problems involving forces and acceleration to reinforce understanding
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BrettL789123
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Two forces F1 and F2 are acting on a mass M=6.0 kg. The force F1 = 7.0i + 5.0j + 6.0k, in N. The acceleration of the mass is given by a = 1.0i + 3.0j + 3.0k, in m/s2. Calculate the magnitude of F2.



I understand that when adding these forces you just add like terms, the i's j's and k's togehter. but what do you do with accel.? do i just subtract F1 like terms with Acell. like terms? never done a problem like this before.
 
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BrettL789123 said:
Two forces F1 and F2 are acting on a mass M=6.0 kg. The force F1 = 7.0i + 5.0j + 6.0k, in N. The acceleration of the mass is given by a = 1.0i + 3.0j + 3.0k, in m/s2. Calculate the magnitude of F2.



I understand that when adding these forces you just add like terms, the i's j's and k's togehter. but what do you do with accel.? do i just subtract F1 like terms with Acell. like terms? never done a problem like this before.

To subtract one vector from another, you do just subtract their components. However, you must be sure to write the vector equation down correctly to make sure you are subtracting the right vectors (and in the right order). What do you get for this problem?
 

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