Calculating Marble's Initial Height Using Projectile Motion Equations

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SUMMARY

The discussion focuses on calculating the initial height from which a marble is thrown horizontally at a speed of 10 m/s, striking the ground at an angle of 68°. The relevant equation used is delta y = (V[SIZE="1"]02 sin2 theta)/(2g), where g represents the acceleration due to gravity. The initial attempts yielded incorrect heights of 4.39 m and 421.24 m. Participants encouraged sharing full calculations to identify errors and provide assistance.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with trigonometric functions, specifically sine
  • Knowledge of the acceleration due to gravity (g = 9.81 m/s²)
  • Ability to manipulate and solve algebraic equations
NEXT STEPS
  • Review the derivation of the projectile motion equations
  • Practice solving problems involving horizontal projectile motion
  • Learn how to apply trigonometric functions in physics problems
  • Explore the effects of different launch angles on projectile motion
USEFUL FOR

Students studying physics, educators teaching projectile motion concepts, and anyone looking to improve their problem-solving skills in kinematics.

IAmSparticus
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Homework Statement


A marble is thrown horizontally with a speed of 10 m/s from the top of a building. When it strikes the ground, the marble has a velocity that makes an angle 68° with the horizontal. From what height above the ground was the marble thrown?



Homework Equations


delta y = (V02 sin2 theta)/(2g)


The Attempt at a Solution


4.39 m and 421.24. Neither correct.
 
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Hi IAmSparticus! :wink:

Show us your full calculations, and then we can see what went wrong, and we'll know how to help! :smile:
 

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