Velocity of water from a hose using projectile motion experiment

[Ben1]

Homework Statement

I'm doing an experiment where I'm trying to determine the velocity of a hose when fully turned on using projectile motion. I projected the hose at different angles (15,30,45,60,75,90 degrees) doing 3 tests on each 1. Here is an example I made with the a set of results -

At an angle of 15 degrees from the ground, a hose is turned on. It has a time of flight of 0.4 seconds and a horizontal range of 2.47 meters.

Homework Equations

horizontal range = v * cos θ * t

The Attempt at a Solution

Horizontal range = v * cos θ * t
2.47 = v * cos 15 * 0.4
v = 2.47 ÷ (cos 15 * 0.4) = 6.392830414 m/s

Is this the TOTAL velocity of the water coming from the hose?

 

[BruceW]

hi Ben, welcome to physicsforums :) yep, that's right, v is the total magnitude of the velocity of water coming from the hose. That's why you used the cos θ to get the horizontal component.