Calculating Mass from Force & Acceleration

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Homework Help Overview

The problem involves calculating the mass of an object given the applied force and the resulting acceleration. The context is rooted in Newton's second law of motion, where the relationship between force, mass, and acceleration is explored.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss identifying the net force and applying Newton's second law. There are attempts to set up equations involving the applied force, gravitational force, and acceleration. Questions arise regarding the need for mass to calculate gravitational force and how to manipulate the equations correctly.

Discussion Status

The discussion is active, with participants providing guidance on setting up equations and algebraic manipulation. Some participants express confusion about eliminating variables and the correct use of gravitational acceleration. There is no explicit consensus on the final approach, but productive dialogue is occurring.

Contextual Notes

Participants are navigating the challenge of working with unknowns in the equations and the implications of using different values for gravitational acceleration. The original poster expresses uncertainty about how to proceed with the calculations.

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Homework Statement


You apply a force of .35N up to lift a fork, the resulting acceleration is .15m/s2. What is the mass in grams.


Please help I don't know where to start with this simple question.
 
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Start with identifying the net force acting on it, and use Newton's 2nd law. Please show an attempt.
 
The net force would not be zero and I am only given the applied force. Without a mass I don't know how I can get the force of gravity.

So as far as I can tell I have .35 Fg = m .15m/s2
 
Let mass = m & use symbols where needed.

What does Newton's 2nd Law say?
 
0.35 Fg = m .15m/s2
0.35 - (m 9.8 m/s2) = m 0.15ms2

The second law says that if the net force is not zero there is an acceleration in the direction of the force.
 
You apply a force of 0.35 N upward.

If the mass of the for is m, what force is gravity exerting downward on the fork?

What is the net force being exerted upon the fork?
 
Wouldn't I need the mass of the fork (m) to calculate the force exerted by gravity?
 
You will have "m" in two places in your equation. Use algebra to solve for m.

I repeat:
What is the net force being exerted upon the fork?​
 
I can get up until
Fapp - m a(gravity) / a(applied) = m
Now I am a bit confused on my next move. Is this right so far? Since m on the left is being multiplied by the acceleration of gravity I think I should divide to get rid of it. But once I do the right side would cancel out to zero.
 
  • #10
Fapp - m g = m a

0.35 - m g = m (0.15)

Not sure what you use for g: 10 m/s2 or 9.8 m/s2 or 9.81 m/s2

Put in the appropriate number for g & solve for m.
 
  • #11
Yes, but as I said earlier I can get up until

0.35 - m g / 0.15 = m

I can't successfully eliminate the LH m. I tried dividing and adding it to the RH
 
  • #12
Before you divide by 'a', your correct equation, per post 5 2nd line, was

0.35 - (m 9.8 m/s2) = m 0.15ms2

leaving off units, then

0.35 - (9.8m) = 0.15m

Now this is algebra, add 9.8m to both sides

0.35 = 9.95m

Now solve for m and convert to grams.
 
  • #13
Thanks, that makes allot of sense.
 

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