Calculating Mass of Little Sister Using Newton's Second Law

Click For Summary

Homework Help Overview

The problem involves calculating the mass of a person (the little sister) being pulled on a sled across a frictionless surface using Newton's Second Law. The original poster provides specific values for force, acceleration, and the mass of the sled.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of Newton's Second Law, particularly how to rearrange the formula to isolate the mass of the little sister. There are attempts to substitute known values into the equation, leading to confusion about the correct result.

Discussion Status

Some participants have offered guidance on rearranging the equation and checking calculations. There is an ongoing exploration of the steps involved, with participants questioning the correctness of their results and the reasoning behind them.

Contextual Notes

Participants note discrepancies between their calculated results and the expected answer, indicating potential misunderstandings in the application of the formula or the interpretation of the problem.

Propaganda777
Messages
10
Reaction score
0
You are pulling your little sister on her sled acroos an icy(frictionless) surface. When you exert a constant horizontal force of 110 N, the sled has an acceleration of 2.5 m/s^2. If the sled has a mass of 7 kg, what is the mass of your little sister?

Heres how I attempted it:
F=110N
A=2.5 m/s^2
M1= 7kg
M2= ?

F=(M1+M2) A
M2= 41.2 kg


The answer is 37 kg, but I can't figure out how to arrive at this mass. Can anyone help me?
 
Physics news on Phys.org
Propaganda777 said:
F=(M1+M2) A
Since you know F and A, you can solve for M1 + M2. Then just subtract out M1.
 
I did, but it comes out to a wrong answer:

F= (m1+m2)a

m2=(F-m1)/a

m2=41.2kg

The answer should be 37 kg, right?
 
Propaganda777 said:
I did, but it comes out to a wrong answer:

F= (m1+m2)a

m2=(F-m1)/a
That last step doesn't follow. Do this:
F = (m1 + m2)a
F/a = m1 + m2

What's that equal?
 
hey it works, thanks you:)
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
23
Views
3K
Replies
17
Views
2K
Replies
13
Views
3K
Replies
44
Views
4K
  • · Replies 42 ·
2
Replies
42
Views
6K
Replies
6
Views
2K
  • · Replies 21 ·
Replies
21
Views
11K
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K