Calculating Mass of Spherical Planet: Solve Confusing Question

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Homework Help Overview

The discussion revolves around calculating the mass of a spherical planet with a density that varies with distance from its center, described by a specific formula. Participants are exploring the implications of this formula and the integration process required to find the total mass.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the method of dividing the planet into spherical shells and integrating to find the total mass. Questions arise regarding the differentiation with respect to radius and the interpretation of the integration process.

Discussion Status

Some guidance has been provided on how to approach the problem, specifically regarding the calculation of the mass of a spherical shell and the subsequent integration. There is an acknowledgment of the complexity of the explanation, with varying levels of clarity among participants.

Contextual Notes

Participants express confusion about the steps involved in the integration process and the overall approach to solving the problem. There is an emphasis on understanding the relationship between the density function and the mass calculation.

jamesbob
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Question: A spehrical planet of Radius R has a density p which depends on the distance r from its centre according to the formula

[tex]p = \frac{p_0}{1 + (r/R)^2}[/tex]​

where [tex]p_0[/tex] is a constant. By dividing the planet up into spherical shells of a small thickness dr, find the mass of the planet.

Ok so I am pretty confused on what I am to do here. Do i differentiate with respect to r?
 
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You want to find the mass of a spherical shell. Then you want to integrate that mass with r going from 0 to R to find the sum of all the spherical shells that make up the planet.
 
Imagine a shell of radius r, thickness dr. For small dr, its volume is approximately the surface area of the shell, [itex]4\pi r^2[/itex], times the thickness, dr: that is [itex]dV= 4\pi r^2 dr[/itex]. Of course, the mass of that shell is the density at that radius times the volume:
[tex]4\pi\frac{p_0 r^2 dr}{1+\left(\frac{r}{R}\right)^2}[/tex]
Integrate that from 0 to R.
 
ok thanks, and that will be the answer because by intergrating i find the sum of all the smaller parts?
 
That's a very rough way of putting it, but okay.
 

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