Calculating Mass Percent in UO2 Nuclear Fuel

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Goldberg
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Homework Statement


Hello guys, I was using mcnp code SERPENT, and while defining materials i encountered a problem. The problem is that for example: if I'm given that i have a 3.5 percent enriched U-235. how do i find the rest of the mass percents of U-234, U-238, O2. Now since i know mass percent of U-235 i can use the equation given below to calculate the mass percent of U-234 in Uranium of that UO2 fuel, and the rest of the uranium would be U-238. But now what would be the weight percent of the Uranium in UO2 fuel?
From research i have found that O2 should be around 66 percent. but i have no way to calculate it. Can you please help. Thank you.

Homework Equations


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The Attempt at a Solution

 
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You can calculate the average mass of an uranium atom with your isotopic mixture. You can look up the average mass of an oxygen atom. With both, you can calculate the average mass of the UO2 group, that should help to get the final answer.
 
mfb said:
You can calculate the average mass of an uranium atom with your isotopic mixture. You can look up the average mass of an oxygen atom. With both, you can calculate the average mass of the UO2 group, that should help to get the final answer.
I got that what do i do after that
 
mfb said:
After getting the final answer?

Can you show what you got?
The thing is that since its UO2, somehow in the answer I am given, U and O and O are divivded out of 100. So O2 is equal to ~66 percent. and as i increase the U-235 content Uranium mass percent increases from the basic ~33.33 percent, and the penalty of that is received by O2 mass percent.
The method you told me to calculate from gives me Uranium of UO2 as ~88 mass percent of the compound which is incorrect. It has to be about 66 percent.
 

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Goldberg said:
The thing is that since its UO2, somehow in the answer I am given, U and O and O are divivded out of 100. So O2 is equal to ~66 percent. and as i increase the U-235 content Uranium mass percent increases from the basic ~33.33 percent, and the penalty of that is received by O2 mass percent.
I don't understand that part.

Oxygen has 67% of the atoms, but its mass fraction is much smaller.
Uranium has about 88% of the mass fraction of UO2, the other 12% are oxygen.
 
mfb said:
I don't understand that part.

Oxygen has 67% of the atoms, but its mass fraction is much smaller.
Uranium has about 88% of the mass fraction of UO2, the other 12% are oxygen.
ok let's try to find the atom percent because the answer is given as ~66 percent oxygen, so that might be an option. because it's definitely not 88 % one.
So how do i get that?
 
mfb said:
UO2 - two out of three atoms are oxygen. 2/3 or 66.7%.
I tried but wasnt able to do it . This is basically the table i want. if i take the number density of O2 and divide by the total i get 66 %. so basically i can either get the number density or this percentage.http://imgur.com/a/2M4HH
 
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I don't understand the problem.

By number of atoms, you have 66.7% oxygen, the result of a trivial calculation as shown above.
By mass, you have 12% oxygen, the result of the calculation you did above.
Those two numbers are not expected to be the same.

Where is the problem now?
 
Ok, The manual for this software is stupid. I know that the table is right so it might be from the number of atoms. Can you tell me how would i go about doing that