Calculating max. kinetic energy (photoelectric)

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SUMMARY

The maximum kinetic energy (K.E.) of electrons ejected from a photoelectric surface can be calculated using the equation K.E. = (hc/λ) - eVo, where h is Planck's constant, c is the speed of light, λ is the wavelength (578 nm), and Vo is the cutoff potential (0.25 V). The initial calculation of K.E. as eVo = 4.0 x 10-20 J is incorrect as it does not account for the energy of the incident photons. To graph the maximum kinetic energy versus frequency, one must calculate multiple points using the derived K.E. values and the corresponding frequencies.

PREREQUISITES
  • Understanding of the photoelectric effect
  • Familiarity with Planck's constant (h = 6.626 x 10-34 J·s)
  • Knowledge of the speed of light (c = 3.00 x 108 m/s)
  • Basic skills in graphing equations
NEXT STEPS
  • Calculate the energy of light radiation using the formula E = hc/λ
  • Determine the maximum kinetic energy of photoelectrons using K.E. = (hc/λ) - eVo
  • Learn how to derive frequency from wavelength using the equation v = c/λ
  • Explore graphing techniques for plotting kinetic energy versus frequency
USEFUL FOR

Students and educators in physics, particularly those studying the photoelectric effect, as well as researchers and professionals involved in photonics and quantum mechanics.

NATSALANE
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given the cutoff potential (0.25 V) and wavelength (578 nm), how do i find the maximum kinetic energy of the electrons ejected from photoelectrif surface, in both eV and J?

my guess is,
KE = e Vo
= (1.6 x 10-19) x (0.25 V)
= 4.0 x 10-20 J

but if i convert that to eV, i get the same value as the cutoff potential - that can't be right.

can someone help me?
 
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also, how do i graph the maximum kinetic energy-vs-frqeuency of photons graph? i only have one value of frequency and kinetic energy. i know that the slope must be the same as the value of plank's constant, but assuming i do not know the constant, how can i find more points on the line to connect?
 
According to the photoelectric equation,
Energy of light radiation = Kinetic Energy of photoelectron + Work function

Here, you are actually calculating the work function and thinking that it is the Kinetic Energy. Calculate the energy of the light radiation [hc/(wavelength)], where h is Planck's constant and c is the speed of light.

Then, subtract work function from the calculated energy to obtain the max. K.E. of the photoelectron.
 
Max K.E. = h(v-vo) = hv - Work function
where h is Planck's constant, v is frequency of radiation and vo is the cutoff frequency. As you have already calculated the work function, therefore you can create the graph (which will be a straight line).
 
alecsing said:
According to the photoelectric equation,
Energy of light radiation = Kinetic Energy of photoelectron + Work function

Here, you are actually calculating the work function and thinking that it is the Kinetic Energy. Calculate the energy of the light radiation [hc/(wavelength)], where h is Planck's constant and c is the speed of light.

Then, subtract work function from the calculated energy to obtain the max. K.E. of the photoelectron.



all i am given is the wavelength and cutoff potential, so in order to find the maximum kin energy, don't i use this equation: Kinetic energy = speed of electron * cutoff potential ?

how does that equate to work?
 
NATSALANE said:
all i am given is the wavelength and cutoff potential, so in order to find the maximum kin energy, don't i use this equation: Kinetic energy = speed of electron * cutoff potential ?

how does that equate to work?

There is a previous thread:- https://www.physicsforums.com/archive/index.php/t-208429.html
. After viewing it, you will be able to understand the meaning of cutoff potential more clearly. It is used to calculate the work function and not the kinetic energy.
 
okay then.

so EK = (hc)/λ - eVo

i got the same answer as W but opposite sign (negative)...
 

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