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- Homework Statement
- What is the minimum height β0 above ground that is required to generate the greatest range shooting horizontally with an angle of 0 degrees and discounting air resistance? π£0 is initial velocity.

- Relevant Equations
- y = h + vt + 0.5a*t^2

vx = v0*cos(theta)

vy = v0*sin(theta) - g*t

I am calculating it like this:

π¦=β0β0.5ππ‘^2=0ββ0=0.5ππ‘^2βπ‘=sqrt(2*β0/g)

π₯=π£0*π‘β substituting t βπ₯=π£0*sqrt(2*β0/g)

ππ₯/πβ0=π£0/(π*sqrt(2*h0/g))=0 for maximum β0=0.

confused. can someone tell me how I am calculating this wrong?

π¦=β0β0.5ππ‘^2=0ββ0=0.5ππ‘^2βπ‘=sqrt(2*β0/g)

π₯=π£0*π‘β substituting t βπ₯=π£0*sqrt(2*β0/g)

ππ₯/πβ0=π£0/(π*sqrt(2*h0/g))=0 for maximum β0=0.

confused. can someone tell me how I am calculating this wrong?