Calculating Maximum Net Force in Simple Harmonic Motion

[denverdoc]

Dark visitor, do you see the similarity between this problem and the engine problem. There we were looking for max velocity. So when you differentiate position with respect to t, the w pops out in front (chain rule) and sin becomes cos. D/dx again and you get -w*w*sin.

Next time you do this, please have all your notes out and for good heavens, my man, don't try to bite off so much in a weekend. Physics requires slow assimilation and lots of practice!

 

[Dark Visitor]

Only one more thing, sorry.

Is the amplitude (A) .160 m? And is \omega equal to\pi/16?

 

[rock.freak667]

Only one more thing, sorry.

Is the amplitude (A) .160 m? And is \omega equal to\pi/16?

yes.

 

[Dark Visitor]

Okay, thanks. Here is my work:

a_max = (\pi/16)²(.160 m)
= .00617 m/s²

F_max = (.64 kg)(.00617 m/s²)
= .003949

or 3.9 * 10^-3

Thanks a lot. I really appreciate all of your help.