Calculating Maximum Velocity of a Dropped Object

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A ball with a mass of 0.5 kg is dropped from a height of 5 meters, and the calculation for its maximum velocity just before impact is discussed. Using the equation vf squared = vi squared + 2ad, the final velocity (vf) is calculated to be approximately 9.8 m/s, with a suggestion to round it to 9.9 m/s. The discussion clarifies that mass does not affect the velocity in free fall under gravity, as all objects accelerate equally regardless of mass. Participants emphasize the importance of distinguishing relevant factors in real-world physics problems. The focus remains on understanding the principles of kinematics rather than the mass of the object.
tengtou
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A ball of mass .5 kg is dropped from a height of 5 m. What is the greatest velocity it will have just before hitting the ground?

vf squared = vi squared + 2ad

vf squared = 0 squared + 2(9.8)(5)

vf = 9.8 m/s

So the greatest velocity is 9.8 m/s, right?

I am still very confuzzled and I think this is the right answer because where did the mass go? Or it doesn't even matter? Can someone verify?

Thanks!
 
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Yes. Mass does not matter in the free fall under gravity. All the body get accelerated equally.
 
Welcome to the forums! No, mass doesn't matter. The acceleration downwards is g, independent of mass, ask Galileo. It's a purely kinematical problem.
 
Thanks! So is my answer correct?
 
Approximately, yes. I would round the answer to 9.9m/sec. But that's a detail.
 
Sweet! Thanks!
 
I don't know why the question had mass in it. Trick question or something haha.
 
In real world problems YOU have to figure out what's important and what isn't. It's just practice.
 

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