Calculating modulus of elasticity?

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To calculate the modulus of elasticity for a cantilevered board, the deflection can be expressed using the formula δ=PL^3/3EI, where P is the applied force, L is the length of the board, E is the modulus of elasticity, and I is the second moment of area. The second moment of area for a rectangular section is calculated as I=(b*h^3)/12, with b as the width and h as the height (thickness) of the board. By measuring the deflection (δ) with a known weight (F), the modulus of elasticity (E) can be derived using the rearranged formula E=I*F*L^3/3δ. This approach allows for comparison of stiffness across different boards based on their dimensions and measured deflections. Understanding these calculations is crucial for evaluating material properties in engineering applications.
tobyrzepka
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I'm trying to figure out how to calculate the modulus of elasticity for a board clamped to a surface plate at one end and free-floating on the other. I've measured the deflection with a 1k weight at the free end of the board. So I've got that data as well as the dimensions of the free-hanging portion of the board.

I've done this test with numerous boards of different thicknesses and dimensions and want to compare them in terms of stiffness.
 
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Hi tobyrzepka, welcome to PF. Try a search for "beam bending equations" to find the deflection vs. Young's modulus for a number of different boundary conditions. For the case of a cantilevered beam (clamped at one end, transverse load on the other), the deflection is \delta=PL^3/3EI, where I=wt^3/12 is the second moment of area. Does this answer your question?
 
Like Mapes stated correctly, δ=F*L^3 / 3E*I

Since you measured deflection you can solve as E (elasticity modulus) and you'll have it.

E=I*F*L^3 / 3δ

F = Force applied (1kg as you mentioned)
L = Length (Length of each board)
E = Elasticity modulus (You will do the math)
I = Inertia moment (b*h^3)/12 where h=width of board and h=height (thickness)
δ= Deflection (As you measured)

I hope that helped
 
So you said :
I = Inertia moment (b*h^3)/12 where h=width of board and h=height (thickness)

I assume you meant b = width of the board, and h = height... is that right?

polymerou said:
Like Mapes stated correctly, δ=F*L^3 / 3E*I

Since you measured deflection you can solve as E (elasticity modulus) and you'll have it.

E=I*F*L^3 / 3δ

F = Force applied (1kg as you mentioned)
L = Length (Length of each board)
E = Elasticity modulus (You will do the math)
I = Inertia moment (b*h^3)/12 where h=width of board and h=height (thickness)
δ= Deflection (As you measured)

I hope that helped
 
b=width, h=depth/height

for a rectangular section I =(b.h^3)/12
 
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