Calculating Molar Concentration of Diluted HCl Solution

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SUMMARY

The molar concentration of a diluted hydrochloric acid (HCl) solution can be calculated using the formula c1v1 = c2v2. In this discussion, 25 mL of 12 M HCl is diluted with 475 mL of distilled water, resulting in a total volume of 500 mL. The correct calculation shows that the final concentration is 0.60 M HCl, as confirmed by multiple participants. The initial assumption of 0.63 M was incorrect due to a misunderstanding of the dilution process.

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If 25 mL of 12 M HCl are added to 475 mL of distilled water, what is the molar concentration of the diluted hydrochloric acid?

c1v1=c2v2
25*12=475c
c=.63 M HCL

book has the answer as .60 M HCL
Isn't the answer .63?
 
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"25*12=475c"

Think about this a moment; you've asserted something different from the problem statement, "25 mL of 12 M HCl are added to 475 mL ---."
 
Your total volume is 500ml, and you have 12 moles. 12moles/.500L is?
 
this seems to work, .30 mol/.500L = .60 M
 
Originally posted by GeneralChemTutor
Your total volume is 500ml, and you have 12 moles. 12moles/.500L is?

No u have 12/40=0.3 moles
and now volume is 500mL

therefore molarity= 0.3*2=0.60

it is right way fish
 

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