Calculating Moments: Finding M_{x} & M_{y} in Ellipse Bounded Region

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The discussion focuses on calculating the moments M_{x} and M_{y} for a region bounded by the ellipse defined by the equation \(\frac{(x-2)^2}{16} + \frac{(y-4)^2}{36} = 1\). The user initially attempted to find the bounds for integration as -2 ≤ y ≤ 10 and -2 ≤ x ≤ 6 but struggled to achieve the correct results. A suggested approach is to change variables to center the ellipse around the origin using u = x - 2 and v = y - 4, which simplifies the integration process.

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City88
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Hi there...
I'm not sure how to go about finding the following moments:

<br /> M_{x}= \int \int\ y dx dy
<br /> M_{y}= \int \int\ x dx dy
Where the region is bounded by the ellipse:
\frac{(x-2)^2}{16}} + \frac{(y-4)^2}{36}} = 1

I tried this several ways. I drew the ellipse and found the bounds to be
-2 \leq y \leq10
-2 \leq x \leq 6

Then I tried integrating with those bounds, but I can't seem to get the right answers. Any help/hints would be greatly appreciated.
 
Last edited:
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Consider changing variables to center the ellipse around zero. eg:
u = x - 2
v = y - 4
 

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