Calculating Net Displacement: How to Find the Final Distance Traveled by Jim?

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Jim's net displacement can be calculated by considering his movements: 100m south, 60m east, and 20m north. The total change in the north-south direction is 80m south (100m south - 20m north), and in the east-west direction, it is 60m east. Using the Pythagorean theorem, the net displacement is approximately 100m, with the direction being southeast. It's important to distinguish between displacement, which is the straight-line distance from the starting point to the endpoint, and the total distance traveled. Understanding these concepts is crucial for solving similar problems.
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Please Help!

Jim walks 100m due south, 60m due east, and then 20m due north. What is his net
displacement (both magnitude and direction)?
 
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first figure out the value of y and x.
 
According to his boots, his net displacement is of course 180 meter, but I know that is not what the (bad) problem designer had in mind :smile:
 
kraaaaamos said:
Jim walks 100m due south, 60m due east, and then 20m due north. What is his net
displacement (both magnitude and direction)?

Is this a homework problem?

Also, does this occur on the Earth, or on a plane?
 
I have no idea. I assume he mans displacement, instead of distance. :S
Is the magnitude of distance the same as displacement?
 
Hint: 60, 80 and 100 constitute a Pythagorean triple.
 
Okay, I think I've got it.
It's kinda like figuring out the hypotenuse?

Thanks everyone : )
 
kraaaaamos said:
Okay, I think I've got it.
It's kinda like figuring out the hypotenuse?

Thanks everyone : )
Displacement means distance between original spot and final spot, "distance traveled" means the length of his entire pathway.
 

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